[Zishi]

Question:


Values from Data Booklet:


What I don't understand is why the Permanganate ions will reduce to Mn(II) ions instead of MnO₂, as stated in the mark scheme? Is it because of the fact that we don't get black/brown solid(MnO₂) at the end of the titration?

[NutterFrutter]

(Original post by Zishi)
Question:


Values from Data Booklet:


What I don't understand is why the Permanganate ions will reduce to Mn(II) ions instead of MnO₂, as stated in the mark scheme? Is it because of the fact that we don't get black/brown solid(MnO₂) at the end of the titration?

I'm guessing your exam board uses the clockwise rule? Edexcel use the anti-clockwise rule (most negative on top of list, most positive at the bottom). Therefore, anything on the left will react with ANYTHING above it and to the right, I apologise if this is confusing.

[thegodofgod]

(Original post by Zishi)
Question:


Values from Data Booklet:


What I don't understand is why the Permanganate ions will reduce to Mn(II) ions instead of MnO₂, as stated in the mark scheme? Is it because of the fact that we don't get black/brown solid(MnO₂) at the end of the titration?

The more positive a reduction potential value is, the better oxidising agent it is. Therefore, it will become reduced more easily, and thus gain electrons more easily.

I think it's just because MnO₄^- is a very strong oxidising agent (compare to the likes of K₂Cr₂O₇), and thus will become reduced very easily to Mn²⁺, instead of Mn⁴⁺ in MnO₂.

[Zishi]

Hmm, seems like Iron(II) is strong enough reducing agent to reduce manganate(VII) ions to manganate(II) ions. Thanks to both of you.