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    \int3xsin2xdx with limits 1/2 pi and zero

    [-3/2cos2x+3/4sin2x] is what i end up as my integral then when i sub the limits i keep getting a three for my answer. Can't get it to latex properly to show my working, but does that integral seem correct?
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    Looks right.
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    (Original post by Brit_Miller)
    Looks right.
    am i just subbing in the limits wrong or something stupid like that; what do you get when you sub the limits into that?
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    (Original post by Emissionspectra)
    am i just subbing in the limits wrong or something stupid like that; what do you get when you sub the limits into that?
    I'll write it out, it just looked right looking at it, I'd better check.
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    (Original post by Emissionspectra)
    \int3xsin2xdx with limits 1/2 pi and zero

    [-3/2cos2x+3/4sin2x] is what i end up as my integral then when i sub the limits i keep getting a three for my answer. Can't get it to latex properly to show my working, but does that integral seem correct?
    I think ur missing an x here. -(3/2)xcos(2x)
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    (Original post by Emissionspectra)
    \int3xsin2xdx with limits 1/2 pi and zero

    [-3/2cos2x+3/4sin2x] is what i end up as my integral then when i sub the limits i keep getting a three for my answer. Can't get it to latex properly to show my working, but does that integral seem correct?
    (Original post by Brit_Miller)
    Looks right.
    Mistake here.

    It should be,  \displaystyle \left[\frac{-3xcos2x}{2}\right] ^{\frac{\pi}{2}}_0 + \left[\frac34sin2x\right]^{\frac{\pi}{2}}_0
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    (Original post by SilentIdea)
    I think ur missing an x here.
    Yep, just realised that when I wrote it out.
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    (Original post by SilentIdea)
    I think ur missing an x here. -(3/2)xcos(2x)
    Ye i see it now urgh ah well got it correct now; thanks

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