integration by parts
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integration by parts
with limits 1/2 pi and zero
[-3/2cos2x+3/4sin2x] is what i end up as my integral then when i sub the limits i keep getting a three for my answer. Can't get it to latex properly to show my working, but does that integral seem correct? -
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Re: integration by partsam i just subbing in the limits wrong or something stupid like that; what do you get when you sub the limits into that?(Original post by Brit_Miller)
Looks right. -
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Re: integration by partsI'll write it out, it just looked right looking at it, I'd better check.(Original post by Emissionspectra)
am i just subbing in the limits wrong or something stupid like that; what do you get when you sub the limits into that?
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Re: integration by partsI think ur missing an x here.(Original post by Emissionspectra)
with limits 1/2 pi and zero
[-3/2cos2x+3/4sin2x] is what i end up as my integral then when i sub the limits i keep getting a three for my answer. Can't get it to latex properly to show my working, but does that integral seem correct?
-(3/2)xcos(2x)
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Re: integration by parts(Original post by Emissionspectra)
with limits 1/2 pi and zero
[-3/2cos2x+3/4sin2x] is what i end up as my integral then when i sub the limits i keep getting a three for my answer. Can't get it to latex properly to show my working, but does that integral seem correct?Mistake here.(Original post by Brit_Miller)
Looks right.
It should be,![\displaystyle \left[\frac{-3xcos2x}{2}\right] ^{\frac{\pi}{2}}_0 + \left[\frac34sin2x\right]^{\frac{\pi}{2}}_0](http://www.thestudentroom.co.uk/latexrender/pictures/2d/2d2ef05c64959cc2688b26bea6033cce.png "\displaystyle \left[\frac{-3xcos2x}{2}\right] ^{\frac{\pi}{2}}_0 + \left[\frac34sin2x\right]^{\frac{\pi}{2}}_0")
-(3/2)xcos(2x)
