Results are out! Find what you need...fast. Get quick advice or join the chat
x

Unlock these great extras with your FREE membership

  • One-on-one advice about results day and Clearing
  • Free access to our personal statement wizard
  • Customise TSR to suit how you want to use it

integration by parts

Announcements Posted on
Rate your uni — help us build a league table based on real student views 19-08-2015
  1. Offline

    ReputationRep:
    \int3xsin2xdx with limits 1/2 pi and zero

    [-3/2cos2x+3/4sin2x] is what i end up as my integral then when i sub the limits i keep getting a three for my answer. Can't get it to latex properly to show my working, but does that integral seem correct?
  2. Offline

    ReputationRep:
    Looks right.
  3. Offline

    ReputationRep:
    (Original post by Brit_Miller)
    Looks right.
    am i just subbing in the limits wrong or something stupid like that; what do you get when you sub the limits into that?
  4. Offline

    ReputationRep:
    (Original post by Emissionspectra)
    am i just subbing in the limits wrong or something stupid like that; what do you get when you sub the limits into that?
    I'll write it out, it just looked right looking at it, I'd better check.
  5. Offline

    ReputationRep:
    (Original post by Emissionspectra)
    \int3xsin2xdx with limits 1/2 pi and zero

    [-3/2cos2x+3/4sin2x] is what i end up as my integral then when i sub the limits i keep getting a three for my answer. Can't get it to latex properly to show my working, but does that integral seem correct?
    I think ur missing an x here. -(3/2)xcos(2x)
  6. Offline

    ReputationRep:
    (Original post by Emissionspectra)
    \int3xsin2xdx with limits 1/2 pi and zero

    [-3/2cos2x+3/4sin2x] is what i end up as my integral then when i sub the limits i keep getting a three for my answer. Can't get it to latex properly to show my working, but does that integral seem correct?
    (Original post by Brit_Miller)
    Looks right.
    Mistake here.

    It should be,  \displaystyle \left[\frac{-3xcos2x}{2}\right] ^{\frac{\pi}{2}}_0 + \left[\frac34sin2x\right]^{\frac{\pi}{2}}_0
  7. Offline

    ReputationRep:
    (Original post by SilentIdea)
    I think ur missing an x here.
    Yep, just realised that when I wrote it out.
  8. Offline

    ReputationRep:
    (Original post by SilentIdea)
    I think ur missing an x here. -(3/2)xcos(2x)
    Ye i see it now urgh ah well got it correct now; thanks

Reply

Submit reply

Register

Thanks for posting! You just need to create an account in order to submit the post
  1. this can't be left blank
    that username has been taken, please choose another Forgotten your password?
  2. this can't be left blank
    this email is already registered. Forgotten your password?
  3. this can't be left blank

    6 characters or longer with both numbers and letters is safer

  4. this can't be left empty
    your full birthday is required
  1. By joining you agree to our Ts and Cs, privacy policy and site rules

  2. Slide to join now Processing…

Updated: April 6, 2012
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Today on TSR

Win a mini-fridge

Don't miss our Freshers competition!

Poll
Do you prefer exams or coursework?
Study resources
x

Looking for some help?

Ask our friendly student community a question

Ask a question now

Or get help from our smart tools and guides

GCSE help A-level help Uni application help Everything else
Quick reply
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.