Step iii 2004 q7

Maths and statistics discussion, revision, exam and homework help.

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  1. David_Skiller's Avatar
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    Step iii 2004 q7
    For the second part.....I can see the equality is deduced by integral by parts but involving which terms?
  2. MHRed's Avatar
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    Re: Step iii 2004 q7
    Might want to go to the STEP prep mega thread, might get more help!
  3. David_Skiller's Avatar
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    Re: Step iii 2004 q7
    .....
  4. David_Skiller's Avatar
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    Re: Step iii 2004 q7
    any1?
  5. gff's Avatar
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    Re: Step iii 2004 q7
    Which inequality?
  6. Aurum's Avatar
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    Re: Step iii 2004 q7
    (Original post by David_Skiller)
    any1?
    I(n+1) is equal to the integral of 

(t^n)/(t+1)^n^+^1

from 0 to 1.
    To obtain the reduction formula (I assume this is what you mean by the equality) we'll need to integrate  1/(t+1)^n^+^1 and differentiate
     t^n
  7. David_Skiller's Avatar
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    Re: Step iii 2004 q7
    (Original post by Aurum)
    I(n+1) is equal to the integral of 

(t^n)/(t+1)^n^+^1

from 0 to 1.
    To obtain the reduction formula (I assume this is what you mean by the equality) we'll need to integrate  1/(t+1)^n^+^1 and differentiate
     t^n
    thanks
  8. gff's Avatar
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    Re: Step iii 2004 q7
    (Original post by gff)
    Which inequality?
    Brainwash, brainwash, watch'ya gonna do, watch'ya gonna do...
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