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Equilibrium

N2O4 (g) ----- 2NO2 (g)
The composition of an equilibrium mixture is 25 mole percent of N2O4. The total pressure of this mixture is 1 * 10^5 N/m2 (1 atm).
(i) calculate the Kp at this temperature.
(ii) Calculate the pressure required to reduce the molar percentage of N2O4 to 10%.
i) partial pressure = mole fraction x total pressure
pp N2O4 = 0.25 x 10^5
pp NO2 = 0.75 x 10^5

Kp = p(NO2)^2/p(N2O4)


Kp = (0.75 x 10^5)^2/(0.25 x 10^5)

Kp = 2.25 x 10^-5
ii) Kp = 2.25 x 10^-5

when molar percentage of N2O4 is 10% molar percentage of NO2 = 90%

let total pressure = P

therefore (0.9 x P)^2/(0.1 x P) = 2.25 x 10^-5

0.81P^2/0.1P = 2.25 x 10^-5

8.1P = 2.25 x 10^-5

Total pressure = 2.78 x 10^-6

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