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M1 Question(Driving Force f=ma)

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    I'm stuck on a question.

    A motorbike and it's rider have a combined mass of 570kg. If the motorbike travels along a straight horizontal road with an acceleration of 3ms^-2, whilst experiencing a resistive force of 135N, what is the driving force of the engine?

    Any help will be much appreciated.

    Thank you
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    F - R = m*a

    F is the driving force
    R is the resistive force
    m is the mass
    a is the acceleration

    It's a simple case of putting the numbers in to the formula.
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    Driving Force- Resistive Force = ma

    F - 135 = 570*3

    F - 135 = 1710

    F = 1845 N

    Hope this helps!

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Updated: April 12, 2012
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