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I'm stuck on a question.
A motorbike and it's rider have a combined mass of 570kg. If the motorbike travels along a straight horizontal road with an acceleration of 3ms^-2, whilst experiencing a resistive force of 135N, what is the driving force of the engine?
Any help will be much appreciated.
F - R = m*a
F is the driving force
R is the resistive force
m is the mass
a is the acceleration
It's a simple case of putting the numbers in to the formula.
Driving Force- Resistive Force = ma
F - 135 = 570*3
F - 135 = 1710
F = 1845 N
Hope this helps!
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