Please choose a topic
Can't see the right topic? Check out All Forums page
Please enter a title
Please enter a message
Find what you need...fast.
Get quick advise or join the chat
Looking for something else? Try the All Forums page
Thanks for posting! View your post here.
Thanks for posting! We just need to check something in your message and will publish it as soon as we can.
Oops! Something went wrong. Please Try again.
I'm stuck on a question.
A motorbike and it's rider have a combined mass of 570kg. If the motorbike travels along a straight horizontal road with an acceleration of 3ms^-2, whilst experiencing a resistive force of 135N, what is the driving force of the engine?
Any help will be much appreciated.
F - R = m*a
F is the driving force
R is the resistive force
m is the mass
a is the acceleration
It's a simple case of putting the numbers in to the formula.
Driving Force- Resistive Force = ma
F - 135 = 570*3
F - 135 = 1710
F = 1845 N
Hope this helps!
6 characters or longer with both numbers and letters is safer
Psst… Don't have an account yet? Create one now, it's free!
We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.
The latest advice and trending discussions are all here
© Copyright The Student Room 2015 all rights reserved
The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.
Register Number: 04666380 (England and Wales), VAT No. 806 8067 22
Registered Office: International House, Queens Road, Brighton, BN1 3XE