C4 integration help, please! :)
Maths and statistics discussion, revision, exam and homework help.
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Re: C4 integration help, please! :)Have you tried the integration by parts method? That should be applicable here ........(Original post by EllaBella<3)
Struggling quite a bit with integration at the moment. Could somebody please explain the question below to me? Any help would be so much appreciated
Integrate: x^1/2 (1+x^1/2) dx -
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Re: C4 integration help, please! :)Ah, i've done it now! Silly mistake not recognising c1 knowledge! Thank you for your quick response though!(Original post by James A)
Have you tried the integration by parts method? That should be applicable here ........
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Re: C4 integration help, please! :)Why would you do that?(Original post by James A)
Have you tried the integration by parts method? That should be applicable here ........
x^1/2(1+x^1/2)= x^1/2 + x -
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Re: C4 integration help, please! :)No it wouldn't. You don't have a function of x where the power of x will reduce to 0 by differentiating.(Original post by James A)
Have you tried the integration by parts method? That should be applicable here ........ -
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Re: C4 integration help, please! :)IBP would work here, but a long winded process for such an easy integral.(Original post by TheJ0ker)
No it wouldn't. You don't have a function of x where the power of x will reduce to 0 by differentiating.Last edited by f1mad; 14-04-2012 at 11:42. -
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Re: C4 integration help, please! :)(Original post by EllaBella<3)
Ah, i've done it now! Silly mistake not recognising c1 knowledge! Thank you for your quick response though!
(Original post by TheJ0ker)
No it wouldn't. You don't have a function of x where the power of x will reduce to 0 by differentiating.
whoops sorry..... I haven't touched C4 Integration in over a month but why can't you use IBP @ f1mad and @TheJ0ker -
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Re: C4 integration help, please! :).(Original post by James A)
whoops sorry..... I haven't touched C4 Integration in over a month but why can't you use IBP @ f1mad and @TheJ0ker
.(Original post by f1mad)
IBP would work here, but a long winded process for such an easy integral.
