The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread

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  1. Trollolollol's Avatar
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    Please explain how? What are you guys doing and what are you missingout?


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  2. Kaiser7's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    Are there any practice papers for FP2, like there were in FP1?

    Are there any new syllabus papers apart from June 09-11, Sariff and the ones Dreamweaver posted?
  3. Trollolollol's Avatar
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    Never mind
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    Last edited by Trollolollol; 16-06-2012 at 22:00.
  4. Omar1994's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    Could anyone explain from this it's p75 in textbook how you get odd even series and what you choose to do? [fp3]
    WTF what's that bro
  5. Trollolollol's Avatar
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    Page from textbook, go have a look at p75 for me? Explain how you get different things for n equal odd and even please?


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  6. Moiraclaire's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
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    I never thought I'd say I have a problem with a series question - I do not understand the answer !
  7. King_Arthur's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    (Original post by Moiraclaire)
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    I never thought I'd say I have a problem with a series question - I do not understand the answer !
    what part of the answer don't u understand..
  8. Omar1994's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    what part of the answer don't u understand..
    how do they cancel down to that?
  9. Victor-PP's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    (Original post by raheem94)
     \cos (3t) = 0 \implies 3t = \arccos(0) = \dfrac{\pi}2

    So the general solutions are  \displaystyle 3t = 2n \pi \pm \frac{\pi}2 \implies t = \frac23 n \pi \pm \frac{\pi}6

    Substituting  n = 15 in  \displaystyle t = \frac23 n \pi - \frac{\pi}6 gives  t \approx \dfrac{59 \pi}{6}

    In part (b) we got,  \displaystyle x = \left( \frac12 + \frac43 t \right) e^{-3t} + \frac1{18} \sin (3t)
    When  t > 30, \ e^{-3t} \to 0

    So sub in  t = \dfrac{59 \pi}6} in  x = \dfrac1{18} \sin (3t) , so you will get  x = - \dfrac1{18}
    Could you please explain where you got n=15 from? Did you just try random values to get t close to 30?
    Last edited by Victor-PP; 17-06-2012 at 00:08.
  10. raheem94's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    (Original post by Victor-PP)
    Could you please explain where you got n=15 from? Did you just try random values to get t close to 30?
    We try some values and see which is the closest, in this case it is n=15.
  11. raheem94's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    (Original post by Victor-PP)
    Could you please explain where you got n=15 from? Did you just try random values to get t close to 30?
    Yes i tried random values.
  12. a5a09's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    Could anyone explain me how to do review exercise question 47b? I did half of it only. Thank you.
  13. Victor-PP's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    (Original post by raheem94)
    We try some values and see which is the closest, in this case it is n=15.
    Alright, man. Thanks!
  14. Moiraclaire's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    (Original post by King_Arthur)
    what part of the answer don't u understand..
    How they cancel through anything. I get their list of terms e.g. 2+0.5-1+1+(1/3)-(3/4)+(1/4)-(3/5)+...+things with n in (all right according to them). THEN WHAT :'(
    How did they get anything to cancel.
  15. sammy_93's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    Hey does anyone have step by step worked solutions for first order differential equations for FP2? I'm having trouble finding the solution curves
    Last edited by sammy_93; 17-06-2012 at 13:41.
  16. Victor-PP's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    Could anyone take a quick look at question 1 from Paper 3 (the ones that Dreamweaver posted)? How the heck do they integrate e^tanx(secx)^2 to just e^tanx ? Am I missing something?
    Last edited by Victor-PP; 17-06-2012 at 12:35.
  17. Omar1994's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    Could anyone take a quick look at question 1 from Paper 3 (the ones that Dreamweaver posted)? How the heck do they integrate e^tanx(secx)^2 to just e^tanx ? Am I missing something?
    chain rule..
  18. raheem94's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    (Original post by Victor-PP)
    Could anyone take a quick look at question 1 from Paper 3 (the ones that Dreamweaver posted)? How the heck do they integrate e^tanx(secx)^2 to just e^tanx ? Am I missing something?
     \displaystyle \int e^{ \tan x }{ \sec^2 x }

    Try differentiating  e^{ \tan x } and you will see why it works.
  19. Rory_M's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    (Original post by Omar1994)
    chain rule..
    Hey just tried that integral out of interest and i have no idea how to do it either, could you elaborate?

    I get that the integral of tanxsecx^2 is 0.5secx^2 but don't know if that's going in the right direction....? the e threw me somewhat!

    EDIT: I see it's (e^tanx)(secx^2) not e^(tanxsecx^2)...
    Last edited by Rory_M; 17-06-2012 at 13:59.
  20. Rory_M's Avatar
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    Re: The Edexcel FP2 (22/06/12 - PM) and FP3 (25/06/12 - PM) Revision Thread
    (Original post by Victor-PP)
    Could anyone take a quick look at question 1 from Paper 3 (the ones that Dreamweaver posted)? How the heck do they integrate e^tanx(secx)^2 to just e^tanx ? Am I missing something?
    so e^2x differentiates to 2e^2x, therefore e^tanx diffs to (diff of tanx)e^tanx.

    Which is secx^2.e^tanx.... then you reverse the differential to give the integral.
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