Algebra with fractions
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Re: Algebra with fractionsYou need to put it all over a common denominator e.g. 6n like you suggested(Original post by krisshP)
I have to find out what n equals for the equation below:
I'm confused on how I start off. This is mainly because of n being the the denominator.
it can't just be six a 'n' is also a common factor between the two. LCM is exactly right 
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Re: Algebra with fractionsOkay. I understand why I have to make 6n be the denominator. But how do I do that. The fact that the 2n and 3n are the denominators puts me off and makes it all hard for me.(Original post by books28)
You need to put it all over a common denominator e.g. 6n like you suggested it can't just be six a 'n' is also a common factor between the two. LCM is exactly right
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Re: Algebra with fractionsI think I worked it out but I'm not sure:
I multiply both sides by 3n, giving the following:
I minus 1 from both sides to give the following:
the Ns on the faction cancel out to give:
This causes in a different form:
Adding 1 to both sides provides:
Then dividing both sides by 21 to get n on its own gives:
Is this a right method or not? -
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Re: Algebra with fractionsYes but horribly long winded. Can you use fractions rather than decimals?(Original post by krisshP)
Then dividing both sides by 21 to get n on its own gives:
Is this a right method or not?
Easier would be just to multiply by 6n.
it can't just be six a 'n' is also a common factor between the two. LCM is exactly right 
