Core Maths 3: Could someone point me in the right direction
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Core Maths 3: Could someone point me in the right directionHi there
I have the following questions;

I can see that these are to do with differentiation, but for (i) do I need to do anything to the formula given, or can I just plug t = 0 straight into this? So the answer for (i) is 0??
And also could someone give me a little clue about working out the other questions as well
Cheers
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Re: Core Maths 3: Could someone point me in the right direction
i) when t = 0, V = 0. Just substitute the t = 0 in to the equation.
ii) Then rate when volume is increasing means do differentiation. Differentiate the equation of V = root(2t + t^2) , After differentiation, substitute t = 1 into differentiated equation.
iii) 10m^3 means volume, V is 10. So, just substitute V = 10 into V = root(2t + t^2) --> original equation. and you can fine the time, t. probably end up with a quadratic. And just take the suitable answer. -
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Re: Core Maths 3: Could someone point me in the right direction(Original post by 3uNic3)
i) when t = 0, V = 0. Just substitute the t = 0 in to the equation.
ii) Then rate when volume is increasing means do differentiation. Differentiate the equation of V = root(2t + t^2) , After differentiation, substitute t = 1 into differentiated equation.
iii) 10m^3 means volume, V is 10. So, just substitute V = 10 into V = root(2t + t^2) --> original equation. and you can fine the time, t. probably end up with a quadratic. And just take the suitable answer.
aww thank you so much