Moments
Maths and statistics discussion, revision, exam and homework help.
-
Moments

Uploaded with ImageShack.us
Can anyone help me with these moments I take about A and get different results to taking them about B
-
Re: MomentsYeah trying to find RA and RB I call em Ay and By(Original post by bcrazy)
Are you considering the reaction forces at A and B? If so, can you show what working you have done?
sum of moments about B=0
(-3x1)+(5x2)-(Ayx3)+(4x4)
Ay=7.6KN
but taking moments about A I get By=1KN and then Ay=5KNLast edited by craglyboy; 18-04-2012 at 23:10. -
Re: MomentsYou need to check your working when taking moments about A...show it if you can't find your mistake. You should find that the force at B is actually acting downwards.(Original post by craglyboy)
Yeah trying to find RA and RB I call em Ay and By
sum of moments about B=0
(-3x1)+(5x2)-(Ayx3)+(4x4)
Ay=7.6KN
but taking moments about A I get By=1KN and then Ay=5KN -
Re: MomentsSo my working for taking moments about B is correct?(Original post by bcrazy)
You need to check your working when taking moments about A...show it if you can't find your mistake. You should find that the force at B is actually acting downwards.
For moments about A I got:
(4x1)+(5x1)-(3x2)-(3xBy)=0
to get By=1KNLast edited by craglyboy; 18-04-2012 at 23:26. -
Re: MomentsFor moments about A I got:(Original post by bcrazy)
Yes
(4x1)+(5x1)-(3x2)-(3xBy)=0
to get By=1KN
but you say this is wrong so is By from equating the forces using Ay=7.6Kn
Sum of Fx=4-7.6+5-3-By=0
By=-1.6KnLast edited by craglyboy; 18-04-2012 at 23:30. -
Re: MomentsIs the bottom part of my last post wrong then as well(Original post by bcrazy)
If you are taking clockwise as positive then then 4kN force should be negative (make sure you always think carefully in terms of clockwise and anticlockwise rather than up and down)
For moments about A I got:
(4x1)+(5x1)-(3x2)-(3xBy)=0
to get By=1KN
but you say this is wrong so is By from equating the forces using Ay=7.6Kn
Sum of Fx=4-7.6+5-3-By=0
By=-1.6Kn -
Re: MomentsSorry, have got confused with your edits which bit you are asking about at the start but your working giving By=-1.6Kn is correct (ignoring the slightly dodgy rounding you did earlier on...should be Ay=23/3 and By=-5/3)(Original post by craglyboy)
Is the bottom part of my last post wrong then as well
For moments about A I got:
(4x1)+(5x1)-(3x2)-(3xBy)=0
to get By=1KN
but you say this is wrong so is By from equating the forces using Ay=7.6Kn
Sum of Fx=4-7.6+5-3-By=0
By=-1.6Kn -
Re: MomentsI was on about resolving the Fx, thanks for the help I think my working is all alright now apart from shoddy rounding as you say.(Original post by bcrazy)
Sorry, have got confused with your edits which bit you are asking about at the start but your working giving By=-1.6Kn is correct (ignoring the slightly dodgy rounding you did earlier on...should be Ay=23/3 and By=-5/3)
Can you show me how you would take moments about A? -
Re: MomentsYeah that was the only reason I did to wasn't very confident and seemingly rightly so thanks anyways now I can start to answer the question, got to find shear force and bending moment now haha thanks man!(Original post by bcrazy)
Sorry, yes! I would have taken moments about A the same as you did when you corrected it...but actually I would have only looked to take moments about B and then resolved vertically- the only reason I would be tempted to take moments about A would be to double check.