S1 Question help

Maths and statistics discussion, revision, exam and homework help.

This thread is sponsored by:
Announcements Posted on
Important: please read these guidelines before posting about exams on The Student Room 28-04-2013
Sign in to Reply
  1. 95_alim's Avatar
    • Exalted Member
    • Posts: 266
    S1 Question help
    can someone kindly explain how i answer this question (in attachment) im very confused and dont know how to solve it.

    so far i done:

    \frac{100-108}{standard  deviation}=0.03

    but what is the 0.03 and how do i go from here on.

    all help appreciated

    thanks
    Attached Thumbnails
    Click image for larger version. 

Name:	s1pic.JPG 
Views:	54 
Size:	17.1 KB 
ID:	142839  
  2. Azland's Avatar
    • Benevolent Member
    • Posts: 763
    Re: S1 Question help
    (Original post by 95_alim)
    can someone kindly explain how i answer this question (in attachment) im very confused and dont know how to solve it.

    so far i done:

    \frac{100-108}{standard  deviation}=0.03

    but what is the 0.03 and how do i go from here on.

    all help appreciated

    thanks
    Take the Z value of 0.97 and put a - sign


    \frac{100-108}{standard  deviation}=-1.881

    I could be wrong, let someone else confirm what I've done.
    Last edited by Azland; 19-04-2012 at 15:17.
  3. 95_alim's Avatar
    • Exalted Member
    • Posts: 266
    Re: S1 Question help
    (Original post by Azland)
    Take the Z value of 0.97 and put a - sign


    \frac{100-108}{standard  deviation}=-1.881

    I could be wrong, let someone else confirm what I've done.

    ok but can u tell me why its -1.88 and not 1.88?

    you maybe right in your working.
  4. Azland's Avatar
    • Benevolent Member
    • Posts: 763
    Re: S1 Question help
    (Original post by 95_alim)
    ok but can u tell me why its -1.88 and not 1.88?

    you maybe right in your working.
    -Z = 1 - P(Z)

    You want the value for 3% so in that case 1 - P(97) = 3%

    Also, if you notice in your question that if you took a positive Z, your SD would be negative which isnt possible.
    Last edited by Azland; 19-04-2012 at 17:06.
  5. 95_alim's Avatar
    • Exalted Member
    • Posts: 266
    Re: S1 Question help
    (Original post by Azland)
    -Z = 1 - P(Z)

    You want the value for 3% so in that case 1 - P(97) = 3%

    Also, if you notice in your question that if you took a positive Z, your SD would be negative which isnt possible.
    hmm kinda makes sense
  6. 95_alim's Avatar
    • Exalted Member
    • Posts: 266
    Re: S1 Question help
    can anyone confirm if the answer provided is correct?
  7. Azland's Avatar
    • Benevolent Member
    • Posts: 763
    Re: S1 Question help
    (Original post by 95_alim)
    can anyone confirm if the answer provided is correct?
    Why dont you just check the mark scheme or the answer sheet from wherever you got the question from.
  8. dz287's Avatar
    • Junior Member
    • Posts: 29
    Re: S1 Question help
    a) working out the standard deviation:

    The general formula is usually
    Z = (X - mean) divided by the standard deviation.

    0.03 is basically the Probability of jars having contents weighing less than 100 grams (3% as they said in the question)

    From the question we know that:
    X = 100g
    Mean = 108g
    Probability = 0.03

    So now we need to know the Z value...
    You can find this out using a Z value calculator on the Internet or from a table of values given to you from your textbook maybe. The Z value for 0.03 = -1.880792

    So now plug in your numbers into the formula:
    -1.880792 = (100 - 108)/standard deviation

    Then re-arrange to get your standard deviation:

    Standard deviation = (100 - 108)/-1.880792

    And that should give you your answer

    Hope that helps
  9. 95_alim's Avatar
    • Exalted Member
    • Posts: 266
    Re: S1 Question help
    (Original post by dz287)
    a) working out the standard deviation:

    The general formula is usually
    Z = (X - mean) divided by the standard deviation.

    0.03 is basically the Probability of jars having contents weighing less than 100 grams (3% as they said in the question)

    From the question we know that:
    X = 100g
    Mean = 108g
    Probability = 0.03

    So now we need to know the Z value...
    You can find this out using a Z value calculator on the Internet or from a table of values given to you from your textbook maybe. The Z value for 0.03 = -1.880792

    So now plug in your numbers into the formula:
    -1.880792 = (100 - 108)/standard deviation

    Then re-arrange to get your standard deviation:

    Standard deviation = (100 - 108)/-1.880792

    And that should give you your answer

    Hope that helps

    yh has definitely helped.

    thanks
  10. Azland's Avatar
    • Benevolent Member
    • Posts: 763
    Re: S1 Question help
    (Original post by 95_alim)
    yh has definitely helped.

    thanks
    I guess he confirmed my answer
  11. dz287's Avatar
    • Junior Member
    • Posts: 29
    Re: S1 Question help
    (Original post by 95_alim)
    yh has definitely helped.

    thanks
    No Problem ^^
  12. chloe2's Avatar
    • New Member
    • Location: London
    • Posts: 7
    Re: S1 Question help
    does anyone have the OCR AS jan 2012 S1 paper and mark scheme by any chance?
Sign in to Reply
Share this discussion:  
Article updates
Moderators

We have a brilliant team of more than 60 volunteers looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Reputation gems:
The Reputation gems seen here indicate how well reputed the user is, red gem indicate negative reputation and green indicates a good rep.
Post rating score:
These scores show if a post has been positively or negatively rated by our members.