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Rate your uni — help us build a league table based on real student views 19-08-2015
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    How would you go about solving this? its supposed to be simple?
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    This is Kirschoff's law - No charge, and so current, accumulates at a node (junction between wires). So the sum of all the currents going in must equal to the sum of all the currents going out.
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    I stands for current

    Its not A becuase that says - I2+I3+I4=I1

    Its not B because that says - I1+I4=I2+I3

    Its not D because that says - I1=I2+I3+I4

    Its C becuase the current comes from I1 and I2 to meet at the middle and leaves at I3 and I4 directing away from the middle
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    Long story short:
    Magnitude of Inwards arrows must equal Magnitude of Outwards arrows

    Edit: Relative to the node.
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    (Original post by BonjournoDeano)
    I stands for current

    Its not A becuase that says - I2+I3+I4=I1

    Its not B because that says - I1+I4=I2+I3

    Its not D because that says - I1=I2+I3+I4

    Its C becuase the current comes from I1 and I2 to meet at the middle and leaves at I3 and I4 directing away from the middle
    Oh! Thanks
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    (Original post by tamimi)
    Long story short:
    Magnitude of Inwards arrows must equal Magnitude of Outwards arrows

    Edit: Relative to the node.

    (Original post by tory88)
    This is Kirschoff's law - No charge, and so current, accumulates at a node (junction between wires). So the sum of all the currents going in must equal to the sum of all the currents going out.
    Thank you

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