Trapezium Rule C2 AQA

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  1. JoeUtd's Avatar
    • Respected Member
    • Posts: 165
    Trapezium Rule C2 AQA
    This should be simple but I can't get to the right answer.

    Q) Using the trapezium rule with 3 ordinates, find an estimate for the area under the curve y = x^2 - 3x from x = 4 to x = 8.

    If there are 3 ordinates, you do 4 (8-4) divided by 3 right? I think that's where I'm going wrong. Then input 4+1.333 and the answer of that + 1.333 as my middle ordinates then x=4 and x=8 as my end points, so I get:

    4 + 2(12.44 + 24.44) + 40 giving me 117... the answer is apparently 80.
  2. mr tim's Avatar
    • Vengeful, Imperial Overlord of The Student Room
    • Location: UK
    • Posts: 4,772
    Re: Trapezium Rule C2 AQA
    you need to do with x = 4,6,8 which would mean that h=2

    then you use the trapezium rule with those values.
  3. JoeUtd's Avatar
    • Respected Member
    • Posts: 165
    Re: Trapezium Rule C2 AQA
    Doing so, I still only get 24. Where am I going wrong?
  4. mr tim's Avatar
    • Vengeful, Imperial Overlord of The Student Room
    • Location: UK
    • Posts: 4,772
    Re: Trapezium Rule C2 AQA
    did you use this formulae:

    \frac{h}{2}(y_0+y_n+2(y_1))

    where h = difference in the x values = 2
    y0 = y value at x = 4
    y1 = y value at x = 6
    yn = y value at x = 8
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