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Binomial Theorem

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  1. Offline

    Hi need some help with a binomial theorem question.

    Evaluate (1-sqrt2)^5. Give your answer in terms of sqrt2

    Using pascals triangle I get

    (x^5)+(5(x^4)y)+(10(x^3)(y^2)+(1 0(x^2)(y^3))+(5x(y^4))+(y^5)

    After substituting in the x and y I get


    But im pretty sure this isnt right?
    Any clues to where im going wrong?
  2. Offline

    I assume you mean

    (x+y)^5 = x^5 + 5x^4y + 10x^3y^2 + 10x^2y^3 + 5xy^4 + y^5

    Then for


    x = 1


    y = -\sqrt{x}

    so you need to check your substitution


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Updated: April 22, 2012
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