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Expanding and factorising

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**** me im glad i wont do maths anymore in my lifetime
ALL hail the calculator!
Original post by zed963
So in order to factorise this it becomes 4(25p2q2+6)[br]=4(5p+q+2)(5pq+3q)[br][br]4(25p^2-q^2+6)[br]=4(5p+q+2)(5p-q+3q)[br][br]


The bottom line is almost perfect. Of course at the end it should be 3 rather than 3q.

I'm guessing that you are pleased that you ended up with almost the correct answer, HOWEVER, several errors in the working have cancelled each other out.

As pointed out earlier these are serious errors rather than just mistakes. The errors were made by nm786

The blind leading the blind.
Original post by nm786
so what does it equal to?


(p + 1/2 )^2

I would write it as:

(p+1/2)(p+1/2)

Then expand it. :smile:
Reply 23
Original post by steve2005
There are several methods of factorising the expression.




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please can you explain this method
Original post by zed963
please can you explain this method


it is difference of 2 squares ... same as i showed you yesterday
Original post by zed963
please can you explain this method


YOU need to study what I have done. Apparently the Iran's are reverse engineering an American Drone, can't you reverse engineer a SIMPLE maths factorisation.


I've just realised that, unlike the Americans, you have three examples to study. Two from me and one from TenOfThem.
(edited 12 years ago)
Reply 26
Original post by TenOfThem
it is difference of 2 squares ... same as i showed you yesterday

(10p+5)2(2q+1)2(10p+5)^2-(2q+1)^2

I understand where you get 10p and 2q from but where do you get +5+1 from
Reply 27
I am f*** blind I just looked at the method again and it clicked.

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