[wibletg]

(Original post by Anon 17)
They delve into the whole one-one aspect of inverse cosh in the book if you're interested.

Looking at the grade boundaries, it seems too easy... I reckon this paper is going to be harder than FP3 was.

The pattern seems to be (with all OCR exams) that they're trying to get people to think outside the box by asking questions differently to what we're used to.

Especially from recent papers.

[queeniemuah]

Well that was bloody hard. Anyone agree with me? Please? lol

[NightBear]

(Original post by queeniemuah)
Well that was bloody hard. Anyone agree with me? Please? lol

Yup. That paper was sent down from my personal hell. I've got about 40 marks (and that's me being generous!)

[Anon 17]

Once again, OCR really needs to sort out their papers. There's no point having past papers if the current papers are barely going to draw from them. I understand the need for having different styles of question and such, but some of the questions here had nothing similar in any past papers or other material.

TSR mark scheme time? I can barely remember my answers already, but I'll try to post some:

5i) Show. (the arcsinh graph question)
ii) Graph was a reflection in the X axis and Y axis (negative version of the graph shown), and the values f(x) could take were larger than 2ln(1+sqrt(2)) and smaller than -2ln(1+sqrt(2)).

8i) Was (x^2 + 4x + 20) / (2x + 4)
ii) Can't remember
iii) Intersected at (2, 2)

[Uncertainty]

pretty tough - worse than january?

[Anon 17]

^ January was an absolute dodle compared to this...

[boromir9111]

Anyone have the paper?

[Sgt.Incontro]

That was almost impossible. I spent so much time studying for this, bloody OCR.

This was posted from The Student Room's Android App on my HTC Sensation Z710e

[Femto]

Haha bloody hard is the way I'd put it!!

[Anon 17]

7iii) was the worst - It only worked if you arranged the ln's in a specific order, and even then I fudged it all to the answer at the end by changing signs from + to - to fit the criteria, so I'm pretty sure I'll get no marks for it anyway.

Some more answers (possibly, if they're wrong I've either remembered incorrectly or I've got them wrong) that I've remembered:

1) arctan(e^2x) + k

2i) Tangents at the pole were theta = 0 and theta = pi/2
ii) I got the max value to be around 0.77 (when theta was 0.65... something I think)
iii) (x^2 + y^2)^2 = 2x^2y (unsimplified, no one I knew could simplify it decently)

3i) x2 and x3 were 1.38... and 1.39... (can't remember exactly), graph was a staircase diagram
ii) Staircase diagram away from the root (curve was an increasing function curving upwards, was below y=x at 1.35 (x1)).
iii) Root was 1.3953 or something like that (last 2 digits probably wrong, can't remember), standard NR method.

[chloe45]

I thought it was okay, but probably only because I went in expecting it to be hell!

[lifesabeach]

Rushed for time as usual, fudged 7 part iii because i couldnt get rid of the ln(n) but i have been told you needed to combine it with the ln(n+1) using laws of logs, which is obvious - silly me

Also, couldn't find the max value of r on the polar co-ordinates, after sketching it & some trial and error with values of theta, i come to the conclusion of max r= pi/5 ? complete guess as the angle was just less than pi/4 at max and thought my chances of getting it right if it was an exact value were higher than a numerical answer!

some of my other answers were vague due to the time constraints & i hope i get lucky with the mark scheme as i need over 86 to get into uni!

[Anon 17]

0.77 is just under pi/4... *Hope*

I think the grade boundaries will be pretty low this time. At least, I hope they are.

Anyone else got answers to contribute?

[wibletg]

Screwed up the last parts of the series of integrals question completely.

The last question only just clicked with about 5 minutes to go. And I cocked up the y coordinate of the graph. (put 4 instead of 2).

Newton Raphson was okay, polar co-ords (apart from the greatest value of r... trial and error anyone?) was okay, first question was okay, the graph question was weird.

Definitely dropped 9 marks, best case scenario I dropped ~15 but worst case I dropped ~20

EDIT: yeah my trial and error was wrong

[DontBeJelBeReem]

Was a decent paper until 7 and 8... Couldn't do much of 7, managed most of 8 except half of the last 4 marker. Hoping for an A.

[wibletg]

On the plus side, I don't know anyone who did the LAST part of the series of integrals question...

A nice reduction formulae though.

[FinKM]

On the plus side I doubt I will ever do quite that badly in an exam ever again. Oh well, at least it was a retake.

[NightBear]

I'd like to think the boundaries will be a fair bit lower than Jan 2012 (which was pretty low, tbh)

[wibletg]

(Original post by FinKM)
On the plus side I doubt I will ever do quite that badly in an exam ever again. Oh well, at least it was a retake.

Same. (at least I hope so!)

(Original post by NightBear)
I'd like to think the boundaries will be a fair bit lower than Jan 2012 (which was pretty low, tbh)

I reckon they'll stay about the same

While there were a couple of questions people struggled with there were also some fairly standard ones.

[CJAW]

(Original post by Anon 17)
Once again, OCR really needs to sort out their papers. There's no point having past papers if the current papers are barely going to draw from them. I understand the need for having different styles of question and such, but some of the questions here had nothing similar in any past papers or other material.

TSR mark scheme time? I can barely remember my answers already, but I'll try to post some:

5i) Show. (the arcsinh graph question)
ii) Graph was a reflection in the X axis and Y axis (negative version of the graph shown), and the values f(x) could take were larger than 2ln(1+sqrt(2)) and smaller than -2ln(1+sqrt(2)).

8i) Was (x^2 + 4x + 20) / (2x + 4) I had half of that so yes.
ii) Can't remember.
iii) Intersected at (2, 2)Yes I got that.

I can't remember 8 iii either.