[Emissionspectra]

(Original post by princess marie)
oh..time up! stil i didnt touch any of c3 questions..

I'm sure you will be fine. C3 isn't that bad.

[MoneyOverEverythin]

(Original post by Emissionspectra)
here

do you happen by any chance have the mark scheme for jan 12 as well?

[Emissionspectra]

(Original post by MoneyOverEverythin)
do you happen by any chance have the mark scheme for jan 12 as well?

No sorry.

[Emissionspectra]

(Original post by Doctor.)
Well I tried but didn't really manage to get it in the correct form. What should I convert the in to?

Sorry I only just saw this, the question says in terms of . So it would be rearrange to get what cos2^2 is equal to

[Doctor.]

(Original post by Emissionspectra)
Sorry I only just saw this, the question says in terms of . So it would be rearrange to get what cos2^2 is equal to

It's cool, wasn't really too bad just needed to look at the other parts of the question and realise you could sub

Thanks anyway

[freakonomics]

(Original post by Smiley Face :))
Hi can someone help me out with
http://pdf.ocr.org.uk/download/pp_10..._gce_4723.pdf?
June 10
Q4 ii
Thanks

integrate between the line x=2 and y=4/x so do integral of (4/x)^2-(2)^2 as it is volume of revolution. Once integrated sub x=6 and x=2 and you should get right answer.

[Sir Grig]

Does anyone have mark scheme for OCR 2012 C3 paper January?


And does anyone knows how to solve this question

tan(θ + 60◦ ) tan(θ − 60◦ ) = 4 sec2 θ − 3,

it is from ocr C3 2007 June

Many thanks for help!

[singingmermaid]

someone help me with question 9i from jan 2012,

[extons]

(Original post by singingmermaid)
someone help me with question 9i from jan 2012,

Think about completing the square on the the function to get it in a form you can see each transformation.

[singingmermaid]

(Original post by extons)
Think about completing the square on the the function to get it in a form you can see each transformation.

it said differentiate it, I did and still got the wrong answer. SMH

[extons]

(Original post by Sir Grig)
Does anyone have mark scheme for OCR 2012 C3 paper January?


And does anyone knows how to solve this question

tan(θ + 60◦ ) tan(θ − 60◦ ) = 4 sec2 θ − 3,

it is from ocr C3 2007 June

Many thanks for help!

Well part i. of that question gives you what the LHS of that equation is equal to. So set what they give you equal to your RHS there, rearrange the equation and use the identities you know (hint: sec^2θ involving tan) and solve.

[extons]

(Original post by singingmermaid)
it said differentiate it, I did and still got the wrong answer. SMH

Aren't you now looking at the second part where they're asking for the range now?

[extons]

(Original post by Emissionspectra)
Sorry I only just saw this, the question says in terms of . So it would be rearrange to get what cos2^2 is equal to

[josh6699]

Really helpful... better than the mark schemes.. worked through answers for each module here!!

http://www.kingsmaths.co.uk/y1213_GL_solutions.htm

[Aimanos]

Can someone please explain why
sec (x) + tan (x) = 0 has no solutions? betweet 0 and 360degrees... I got 270?

[Doctor.]

(Original post by josh6699)
Really helpful... better than the mark schemes.. worked through answers for each module here!!

http://www.kingsmaths.co.uk/y1213_GL_solutions.htm

Awww no 2012 stuff yet i was just getting my Printer ready to get them ah well. thanks for the site!

[Sem193]

(Original post by Aimanos)
Can someone please explain why
sec (x) + tan (x) = 0 has no solutions? betweet 0 and 360degrees... I got 270?

I squared then to get sec^2(x) + tan^2(x)=0. Sec^2(x)=1+tan^2(x) so I rewrote the equation in terms of tan(x) and got 1+2tan^2(x)=0. Then I got tan^2(x)=-0.5 which would be a Math error on my calculator so I took that to mean there were no solutions. I don't know if that's right though...

[Sem193]

I really hope the paper's nicer than the January 2012 one

[Aimanos]

(Original post by Sem193)
I really hope the paper's nicer than the January 2012 one

yh same btw are you allowed to just square things?
and ty for answering my question

[Sem193]

(Original post by Aimanos)
yh same btw are you allowed to just square things?
and ty for answering my question

I have no idea. That's what I just though of doing. What paper was that question from?