one question from a past paper: what is the effect on rate of reaction when using an immobilised enzyme and enzyme free in solution if the temperature remains constant?
you could use collision theory to answer this. The immobilised enzyme is immobilised i.e. it can't move this means that this immobilisation will limit the amount of collisions that can occur between the substrate and the active site of the enzyme. Less collisions means less products in the given time, therefore rate will be slower if immobilised than if it is free.
If the enzyme is immobilised is a substance such as sodium alginate you could talk about diffusion distance. In the immobilised enzyme, the enzyme is surrounded by the alginate to form a bead. It will take time for the substrate to diffuse through the alginate and reach the enzyme therefore the rate of the retain of the immobilised enzyme (relative to the free enzyme) is slower.
All this is provided that the temperature isn't high enough to denature the free enzyme so even if the temperature is constant you've got to make sure it isn't too high in the first place to cause denaturation.
Thanks for posting! You just need to create an account in order to submit the post
Already a member?
Oops, something wasn't right
please check the following:
Not got an account?
Sign up now
© Copyright The Student Room 2016 all rights reserved
The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.
Register Number: 04666380 (England and Wales), VAT No. 806 8067 22
Registered Office: International House, Queens Road, Brighton, BN1 3XE