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Count rate

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    What would the count rate be after for 24 seconds for source A

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    I don't know how to get the answer help.
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    Find the half life of source 1 from the graph (4 seconds) ans then find the decay constant by doing ln2/Half life

    Then use this in the equation A = A0 * e^-kt where K=decay constant, t=24 and A0=origional count rate = 80

    A=80*e^-(ln2/T)24
    A=1.3ish
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    (Original post by 05sykesd)
    Find the half life of source 1 from the graph (4 seconds) ans then find the decay constant by doing ln2/Half life

    Then use this in the equation A = A0 * e^-kt where K=decay constant, t=24 and A0=origional count rate = 80

    A=80*e^-(ln2/T)24
    A=1.3ish
    The answer is 15 but I don't know how to get to that answer.
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    (Original post by zed963)
    What would the count rate be after for 24 seconds for source A

    Click image for larger version. 

Name:	Count rate.JPG 
Views:	30 
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ID:	145619

    I don't know how to get the answer help.
    How long does it take for the activity of A to fall to half? (120 to 60)
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    8 seconds


    24 seconds is a whole number of this half-lives.
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    It's 3 half lives. 24 = 3 x 8

    Each half life means the count rate is halved.
    So what is it after that many half lives.
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    Damn! did it for the wrong source -_________- one day ill learn to read!!!
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    (Original post by Stonebridge)
    How long does it take for the activity of A to fall to half? (120 to 60)
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    8 seconds


    24 seconds is a whole number of this half-lives.
    Spoiler:
    Show
    It's 3 half lives. 24 = 3 x 8

    Each half life means the count rate is halved.
    So what is it after that many half lives.
    i'm not following.
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    (Original post by zed963)
    i'm not following.
    Look at the graph for A.
    The activity falls from 120 to 60 in 8 seconds.
    That means 8 seconds is one half life because that's how long it takes the activity to fall to half the original value.
    That means, every 8 seconds the activity halves.
    So after 8 seconds its activity is 60
    After another 8 seconds (=16 seconds) the activity will halve again. (to 30)
    What will it be after 24 seconds?
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    (Original post by Stonebridge)
    Look at the graph for A.
    The activity falls from 120 to 60 in 8 seconds.
    That means 8 seconds is one half life because that's how long it takes the activity to fall to half the original value.
    That means, every 8 seconds the activity halves.
    So after 8 seconds its activity is 60
    After another 8 seconds (=16 seconds) the activity will halve again. (to 30)
    What will it be after 24 seconds?
    15.

    I'm getting confused with Becquerel and count rate please can u define it.
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    (Original post by zed963)
    15.

    I'm getting confused with Becquerel and count rate please can u define it.
    Becquerel is a measure of activity and is the number of disintegrations per second.
    Count rate (from a detector) gives a measure of how the activity of a sample is varying.

    Count rate does not equal activity in becquerel because the detector will not detect all the disintegrations.
    However, count rate is a measure of activity.
    If the count rate drops to half then the activity of the sample has dropped to half.
    That's what is happening in this question. The count rate tells us the activity has fallen to half after 8 seconds.
    It does not tell us the activity in becquerel, though.

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