Correct method?
Power = Work done/Time
Work done = (1/2)mv2
so in terms of units;
work done = kg((m/s)2)
∴ work done = kg (m2 s-2)
so Power = kg m2 s-2 / s
so Power = kg m2 s-3
so answer is C?
Original post by bssjonny
yup!
Thanks
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