Rearanging nightmare.
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Rearanging nightmare.
I can't for the life of me rearrange the following equation. It is part of a differentiation question where I need to create a formula for volume, V. The question is as follows;
A closed cylinder has a total surface area of 600 pi. show that the volume of this cylinder is given by the formula V= 300πr - πr^3
r= radius of cylinder
I know that;
A = 2πrh(2πr^2)
V = πr^2h
therefore
600π = 2πrh(2πr^2) - I need to rearrange this on the left to make h the subject so i can plug it into the volume formula to give me V= 300πr - πr^3.
I've tried a thousand ways but can't seem to get it, please help before I crack! :-? -
Re: Rearanging nightmare.(Original post by monkfishkev)
I can't for the life of me rearrange the following equation. It is part of a differentiation question where I need to create a formula for volume, V. The question is as follows;
A closed cylinder has a total surface area of 600 pi. show that the volume of this cylinder is given by the formula V= 300πr - πr^3
r= radius of cylinder
I know that;
A = 2πrh(2πr^2)
V = πr^2h
therefore
600π = 2πrh(2πr^2) - I need to rearrange this on the left to make h the subject so i can plug it into the volume formula to give me V= 300πr - πr^3.
I've tried a thousand ways but can't seem to get it, please help before I crack! :-?
Surface Area(Original post by monkfishkev)
I can't for the life of me rearrange the following equation. It is part of a differentiation question where I need to create a formula for volume, V. The question is as follows;
A closed cylinder has a total surface area of 600 pi. show that the volume of this cylinder is given by the formula V= 300πr - πr^3
r= radius of cylinder
I know that;
A = 2πrh(2πr^2)
V = πr^2h
therefore
600π = 2πrh(2πr^2) - I need to rearrange this on the left to make h the subject so i can plug it into the volume formula to give me V= 300πr - πr^3.
I've tried a thousand ways but can't seem to get it, please help before I crack! :-?
Not
And how have you let
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