Mechanics

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  1. Sarmi's Avatar
    • Junior Member
    • Posts: 39
    Mechanics
    A wrecking ball of mass 250kg is being used to knock down a brick wall. The ball hits the wall at a velocity of 4m/s. After impact, if three 20kg blocks of wall move at a velocity of 2m/s and two 40kg blocks of wall move at a velocity of 3m/s, using the conservation of momentum, calculate the velocity of the wrecking ball after impact.
    Give your answer correct to two decimal places.

    Need help please...
  2. F1Addict's Avatar
    • Peer Of The TSR Realm
    • Posts: 1,744
    Re: Mechanics
    In simple terms,

    Momentum = mass x velocity

    The consevation of momentum states that:
    Total Momentum Before = Total Momentum After

    Does this help?
  3. oo00oo's Avatar
    • Adored and Respected Member
    • Posts: 477
    Re: Mechanics
    The total momentum before impact must be the same as the total momentum after impact.

    Before impact, the only thing moving is the wrecking ball... and it's momentum is  p_b = 250 \times 4 = 1,000 kg m/s^2 .

    After impact, the wrecking ball is moving with velocity v, and we also have all the bricks with their masses and velocities, so total momentum after is:

     p_a = 250 v + 3 \times 20 \times 2 + 2 \times 40 \times 3

    Since  p_a = p_b

    We can say:

      250 v + 3 \times 20 \times 2 + 2 \times 40 \times 3 = 1000

    One equation, one unknown ... solve for  v.
  4. Sarmi's Avatar
    • Junior Member
    • Posts: 39
    Re: Mechanics
    yh...i got the answer as v=2.56ms-1. Is this right?
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