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1. OCR M1 - 31st May 2012 :)
Haven't seen one of these for this exam... post the M1 problems up on here for OCR ...
2. Re: OCR M1 - 31st May 2012 :)
I'm doing M1 also at this time

It is by far the most difficult out of the 4 units I am doing this summer IMO (m1,s1,d1,c2) because I find it hard to understand what the question is actually asking for, and some of the latter examples are very complicated :/

I have no questions I am doing that I am stuck on at the moment, but GL on your revision!
3. Re: OCR M1 - 31st May 2012 :)
(Original post by Genesis2703)
I'm doing M1 also at this time

It is by far the most difficult out of the 4 units I am doing this summer IMO (m1,s1,d1,c2) because I find it hard to understand what the question is actually asking for, and some of the latter examples are very complicated :/

I have no questions I am doing that I am stuck on at the moment, but GL on your revision!
Post it up.. lets try and solve it
4. Re: OCR M1 - 31st May 2012 :)
How would I solve this question guys?

I get a = 39.2 ms^-2 and T = 147 N but they don't seem right...
Attached Thumbnails

5. Re: OCR M1 - 31st May 2012 :)
(Original post by PeterStoba)
How would I solve this question guys?

I get a = 39.2 ms^-2 and T = 147 N but they don't seem right...

I got a = 2.45m/s/s
AND t = 36.75N

6. Re: OCR M1 - 31st May 2012 :)
(Original post by Smiley Face :))
I got a = 2.45m/s/s
AND t = 36.75N

I also get the same answers.
7. Re: OCR M1 - 31st May 2012 :)
(Original post by raheem94)
I also get the same answers.
Wooop! First time my answers match with u boss
8. Re: OCR M1 - 31st May 2012 :)
I do not know, the mark scheme is unavailable. I know my answer is wrong.

What method did you use?
9. Re: OCR M1 - 31st May 2012 :)
(Original post by PeterStoba)
I do not know, the mark scheme is unavailable. I know my answer is wrong.

What method did you use?
See the diagram in the spoiler:

Spoiler:
Show

Now form 2 equations,
First consider the 5kg particle,

Now consider the 3kg particle,

Now solve simultaneously.
Last edited by raheem94; 08-05-2012 at 18:22. Reason: Typo
10. Re: OCR M1 - 31st May 2012 :)
I don't see where 7 has came from here? But...

Equation 1 x3, 15g - 21 = 15a
Equation 2 x5, 5T - 15g = 15a

15g - 21 = 5T - 15g
(30g - 21) / 5 = T
T = 54.6?

I must be missing something?
11. Re: OCR M1 - 31st May 2012 :)
Peter, the 7 was meant to be a T. I think Raheem made a typing error.

Try it again with 5g - T = 5a instead of with a 7
12. Re: OCR M1 - 31st May 2012 :)
Haha I look like an idiot now! I was honestly confused as to where 7 came from.

Right so now I get the correct answers! Thanks everyone :-)
13. Re: OCR M1 - 31st May 2012 :)
(Original post by PeterStoba)
I don't see where 7 has came from here? But...

Equation 1 x3, 15g - 21 = 15a
Equation 2 x5, 5T - 15g = 15a

15g - 21 = 5T - 15g
(30g - 21) / 5 = T
T = 54.6?

I must be missing something?
Sorry, it was a typo.

(Original post by Genesis2703)
Peter, the 7 was meant to be a T. I think Raheem made a typing error.

Try it again with 5g - T = 5a instead of with a 7
Thanks for clearing the doubt.
14. Re: OCR M1 - 31st May 2012 :)
(Original post by PeterStoba)
Haha I look like an idiot now! I was honestly confused as to where 7 came from.

Right so now I get the correct answers! Thanks everyone :-)
haha Don't worry about it man!

Oh and in class we went over an m1 paper we did for HW/in class, and I got 100%.. but I feel bad because Of course I asked for help on the harder questions, and struggle a lot when left alone. I feel like I am giving the teacher the wrong impression tbh (It was the Jan 2011 paper btw)
15. Re: OCR M1 - 31st May 2012 :)
Just let him know you got some help on a few of the questions and you don't feel you'd get 100% on your own / another paper?

I think you are all doing OCR? I'm MEI, just realised!

16. Re: OCR M1 - 31st May 2012 :)
(Original post by PeterStoba)
Just let him know you got some help on a few of the questions and you don't feel you'd get 100% on your own / another paper?

I think you are all doing OCR? I'm MEI, just realised!

Unless you mean angle of the resultant force then no I do not think OCR covers that in M1. You could post a question and see if we know though... but I think we will not understand it :P
17. Re: OCR M1 - 31st May 2012 :)
(Original post by Smiley Face :))
Haven't seen one of these for this exam... post the M1 problems up on here for OCR ...

(Original post by Genesis2703)
I'm doing M1 also at this time

It is by far the most difficult out of the 4 units I am doing this summer IMO (m1,s1,d1,c2) because I find it hard to understand what the question is actually asking for, and some of the latter examples are very complicated :/

I have no questions I am doing that I am stuck on at the moment, but GL on your revision!

(Original post by raheem94)
I also get the same answers.
hi guys im also doing this paper. i have a quick question; are we allowed to use this formula for tension - T=mg+ma ? thanks a lot.
18. Re: OCR M1 - 31st May 2012 :)
(Original post by ugk4life)
hi guys im also doing this paper. i have a quick question; are we allowed to use this formula for tension - T=mg+ma ? thanks a lot.
You have to form the equation by considering the situation, there isn't a general formula which will apply to all situations.

Always draw a diagram and resolve the forces, to get the equations.

And by the way, i am not doing this exam.
19. Re: OCR M1 - 31st May 2012 :)
(Original post by raheem94)
You have to form the equation by considering the situation, there isn't a general formula which will apply to all situations.

Always draw a diagram and resolve the forces, to get the equations.

And by the way, i am not doing this exam.
ok thanks, my friend told me this formula so i was wondering if this can apply to all situations.

guess ill have to stick with drawing the diagrams and stuff lol.
20. Re: OCR M1 - 31st May 2012 :)
(Original post by raheem94)
I also get the same answers.
Hey, Could u helpme out please.

June 11
Q2 part 4
I have got that P will further go up by 0.036 M. I then added this to the 0.36M to get 0.396M.. In order to get the greastest height of P
However the markscheme has said that the greatest height of P is 0.756 M
I don't understand how and why they have got that value...