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Circle / radius question (3 marks) ????

Can you show me how to answer this?

question 1.png

I know the forumla

(x-h)^2 + (y-k)^2 = r^2

:biggrin:

Thanks.

Scroll to see replies

Reply 1
Original post by blueray
Can you show me how to answer this?

question 1.png

I know the forumla

(x-h)^2 + (y-k)^2 = r^2

:biggrin:

Thanks.


1. Complete the square for X and Y.

2. Simultaneous equations
First rearrange the equation so that it looks like (x-h)^2 + (y-k)^2 = r^2. I find the easiest method is to use 'completing the square'.
Reply 3
Original post by USB
1. Complete the square for X and Y.

2. Simultaneous equations



Original post by CharlieBoardman
First rearrange the equation so that it looks like (x-h)^2 + (y-k)^2 = r^2. I find the easiest method is to use 'completing the square'.


I know you have to complete the square and I have put it in the form

x^2-2x + y^2 - 4y - 20 = 0

But how do I do that?

All the videos I have seen for it are for totally different non related questions.
Original post by blueray
I know you have to complete the square and I have put it in the form

x^2-2x + y^2 - 4y - 20 = 0

But how do I do that?

All the videos I have seen for it are for totally different non related questions.

Here is some clue :smile:

Spoiler


Let me know if you want more help
(edited 11 years ago)
Reply 5
Original post by CharlieBoardman
Here is some clue :smile:

Spoiler


Let me know if you want more help


How did you get (x1)21(x-1)^2-1
And (y2)24(y-2)^2-4
in the first place?
Original post by blueray
How did you get (x1)21(x-1)^2-1
And (y2)24(y-2)^2-4
in the first place?


Well, let's take the x's for example. We want to complete the square of x22xx^2-2x

To do this, I put (x - half of the coefficient of x from the above equation), and squared. (x1)2(x-1)^2 but, this equals x22x+1x^2-2x+1 so I added -1 on the end to make them equal :smile: repeat process
(edited 11 years ago)
Reply 7
Ok lets go back a step

Can you complete the square

Can you re-write x2+4x5x^2 + 4x - 5

in the form (x+a)2+b(x+a)^2 + b
Reply 8
Original post by CharlieBoardman
Well, let's take the x's for example. We want to complete the square of x22xx^2-2x

To do this, I put (x - half of the coefficient of x from the above equation), and squared. (x1)2(x-1)^2 but, this equals x22x+1x^2-2x+1 so I added -1 on the end to make them equal :smile: repeat process


Oh yeah I remember now :biggrin: Will do that!
Original post by blueray
Oh yeah I remember now :biggrin: Will do that!


Then try and use substitution for ii) :smile:
What paper is this coz my ACB is coming out really weird
Got it now! U had to use trigonometry; I htought it was some common sense thing
Reply 12
Original post by TenOfThem
Ok lets go back a step

Can you complete the square

Can you re-write x2+4x5x^2 + 4x - 5

in the form (x+a)2+b(x+a)^2 + b



Original post by CharlieBoardman
Then try and use substitution for ii) :smile:



Original post by GreenLantern1
Got it now! U had to use trigonometry; I htought it was some common sense thing


How do I do part ii) Can you go through it? :biggrin: THanks!
Original post by blueray
How do I do part ii) Can you go through it? :biggrin: THanks!


You know that y=x+2 so just sub it in to the equation you found after having completed the square. That should work out pretty nicely
Reply 14
Original post by GreenLantern1
You know that y=x+2 so just sub it in to the equation you found after having completed the square. That should work out pretty nicely


Yeah my bad. I see it sorry guys.
Reply 15
Original post by GreenLantern1
Got it now! U had to use trigonometry; I htought it was some common sense thing



Original post by CharlieBoardman
Then try and use substitution for ii) :smile:



Original post by TenOfThem
Ok lets go back a step

Can you complete the square

Can you re-write x2+4x5x^2 + 4x - 5

in the form (x+a)2+b(x+a)^2 + b


Ok so I found A and B for part ii) And C from part i)

How do I do part iii) ? :biggrin:

Thanks!
Original post by blueray
Ok so I found A and B for part ii) And C from part i)

How do I do part iii) ? :biggrin:

Thanks!


sine my brutha!
Reply 17
Original post by GreenLantern1
sine my brutha!


Yeah I know SOH sine etc

but how do i get there? :smile:

a = (4,6) b = (-3,-1) c = (1,2)
Original post by blueray
Yeah I know SOH sine etc

but how do i get there? :smile:

a = (4,6) b = (-3,-1) c = (1,2)


Use pythag to figure out side lengths first :smile:
You know AC and BC (since they are radii)

You can find AB (Pythag)

Then a bit of trig ... either cosine rule or half an isosceles triangle

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