[MSI_10]

If I don't get part A correct, I'm screwed for the rest of the questions.

Is it tan inverse 6/8 ?? ie 36.9 degrees? (3SF)

[Hopple]

Where do you get the 8 from? Use toa.

[MSI_10]

(Original post by Hopple)
Where do you get the 8 from? Use toa.

So its tan inverse 6/10?

IDK but I put the velocity of 8 as part of the triangle then assumed 10 must have been the hyptonuse, so i thought 8 was the adjacent :|

[Hopple]

(Original post by MSI_10)
So its tan inverse 6/10?

Yeah, that's it.

[the bear]

yes tanα is 6/10

[MSI_10]

(Original post by Hopple)
Yeah, that's it.

Aight thanks.

Am I starting part b probably; to get time, first need to use S. Do I use 6 or 10..?

Then SUVAT (S=ut+o.5at^2) use quadratic formula to get t?

[Hopple]

(Original post by MSI_10)
Aight thanks.

Am I starting part b probably; to get time, first need to use S. Do I use 6 or 10..?

Then SUVAT (S=ut+o.5at^2) use quadratic formula to get t?

For part b, are you looking at vertical or horizontal motion (or both)? And yes, that suvat equation will do.

[MSI_10]

(Original post by Hopple)
For part b, are you looking at vertical or horizontal motion (or both)? And yes, that suvat equation will do.

I did this..
S=-6
a=-9.8
U=8sin31..

-6=8sin31t-4.9t^2
-4.9^2+8sin31t+6=0
got t=1.60 or t=-0.763

Answer t=1.60..?

[Hopple]

(Original post by MSI_10)
I did this..
S=-6
a=-9.8
U=8sin31..

-6=8sin31t-4.9t^2
-4.9^2+8sin31t+6=0
got t=1.60 or t=-0.763

Answer t=1.60..?

Make sure you're measuring everything in the same direction.

[MSI_10]

(Original post by Hopple)
Make sure you're measuring everything in the same direction.

:\

[Hopple]

(Original post by MSI_10)
:\

Even though everything's going downwards, you've made displacement and acceleration be in the opposite direction to initial velocity.

[MSI_10]

(Original post by Hopple)
Even though everything's going downwards, you've made displacement and acceleration be in the opposite direction to initial velocity.

Oh that's what you meant, yeah i get what you mean now thanks

So t=0.763

[MSI_10]

Hmm, can anyone check if im doing part c correctly.

It's asking for distance.. do I use the time obtained from part b, use S=ut+1/2at^2 but use 8cos31 for u instead of 8sin31..?

[finality]

(Original post by MSI_10)
Hmm, can anyone check if im doing part c correctly.

It's asking for distance.. do I use the time obtained from part b, use S=ut+1/2at^2 but use 8cos31 for u instead of 8sin31..?

Yes, but remember there are no forces acting horizontally here.

[MSI_10]

(Original post by finality)
Yes, but remember there are no forces acting horizontally here.

Alright so I used 8sin31
I get the answer as 6m. Something tell's me this aint right; it seems to high :\