Quick help with the domain please

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  1. Nodes Of Ranvier's Avatar
    • Junior Member
    • Posts: 38
    Quick help with the domain please
    Two parametric equations:

    X=2cot(t) Y=2sin^2(t) where 0<t<(or equal to)pi/2

    gives the Cartesian equation y=8/(x^2+4)

    What is the domain of the curve?

    The answer is X>0 but I don't understand why? I thought it would have been all real values of X.

    Is it something to do with the limits of t?

    Thank you.
  2. TenOfThem's Avatar
    • No --- I am a Newbie --- Honest
    Re: Quick help with the domain please
    Given the acceptable values of t ... what values can x take?
  3. Nodes Of Ranvier's Avatar
    • Junior Member
    • Posts: 38
    Re: Quick help with the domain please
    (Original post by TenOfThem)
    Given the acceptable values of t ... what values can x take?
    So I get X=0 and no answer when I subtitute pi/2 to find X.

    How does this make the domain X>0?

    Thanks for answering btw
  4. TenOfThem's Avatar
    • No --- I am a Newbie --- Honest
    Re: Quick help with the domain please
    What does Tan do between 0 and 90

    So what does Cot do
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