Quick help with the domain please
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Quick help with the domain please
Two parametric equations:
X=2cot(t) Y=2sin^2(t) where 0<t<(or equal to)pi/2
gives the Cartesian equation y=8/(x^2+4)
What is the domain of the curve?
The answer is X>0 but I don't understand why? I thought it would have been all real values of X.
Is it something to do with the limits of t?
Thank you.
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Re: Quick help with the domain pleaseSo I get X=0 and no answer when I subtitute pi/2 to find X.(Original post by TenOfThem)
Given the acceptable values of t ... what values can x take?
How does this make the domain X>0?
Thanks for answering btw