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C2 Logs
Given that loga (x + 4) = loga x/4 + loga 5,
and that loga (y + 2) = loga 12 − loga (y + 1),
where y > 0, find
a) the value of x,
b) the value of y,
c) the value of the logarithm of x to the base y.
Rep will be given!
and that loga (y + 2) = loga 12 − loga (y + 1),
where y > 0, find
a) the value of x,
b) the value of y,
c) the value of the logarithm of x to the base y.
Rep will be given!
Fenchurch
Given that loga (x + 4) = loga x/4 + loga 5,
and that loga (y + 2) = loga 12 − loga (y + 1),
where y > 0, find
a) the value of x,
b) the value of y,
c) the value of the logarithm of x to the base y.
Rep will be given!
and that loga (y + 2) = loga 12 − loga (y + 1),
where y > 0, find
a) the value of x,
b) the value of y,
c) the value of the logarithm of x to the base y.
Rep will be given!
a) loga(x + 4) = loga(5x/4) (mulitply the thing in brackets when adding logs - hope that makes sense)
then, (loga(x + 4))/log(5x/4) = 1 1=loga of a
so a = 4(x+4)/5x 5ax=4x+16
x(5a-4)=16 so x = 16/(5a-4)
If that makes sense, i think thats the ans
Fenchurch
Given that loga (x + 4) = loga x/4 + loga 5,
and that loga (y + 2) = loga 12 − loga (y + 1),
where y > 0, find
a) the value of x,
b) the value of y,
c) the value of the logarithm of x to the base y.
Rep will be given!
and that loga (y + 2) = loga 12 − loga (y + 1),
where y > 0, find
a) the value of x,
b) the value of y,
c) the value of the logarithm of x to the base y.
Rep will be given!
b)same applies for this one. when takin 1log away from another u divide the thing that the log is of
so, loga (y+2)=loga (12/(y+1)) take away loga (y+2)
0 = loga ((12/y+1)/(y+2)
0 = loga ((12/y+1)/(y+2)
so, 0=((12/y+1)/(y+2)
12/y^2+3y+2=0
My brain hurts Hope i've helped a bit but i'm stuck. I would be interested in the answer when u get it. Hope my working has helped a little....... Head hurts so much don't think i can cope with c) at the mo.Related discussions
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