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Quick question about UMS

Hello. I heard somewhere that...

90% of the ums e.g 81/90 you would do: Raw mark for A + (Raw mark for A - Raw mark for B)

100% ums: Raw mark for A + 2x(Raw mark for A - Raw mark for B)

Is this true? Thanks x
Reply 1
Original post by nereik6794
Hello. I heard somewhere that...

90% of the ums e.g 81/90 you would do: Raw mark for A + (Raw mark for A - Raw mark for B)

100% ums: Raw mark for A + 2x(Raw mark for A - Raw mark for B)

Is this true? Thanks x


This tends to work in most cases for OCR (as far as I know). I know only of this for Physics and Chemistry exams, coursework is often different. :smile:
Reply 2
Cheers mate x

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