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Unbiased estimator of linear contrast

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I'm getting really muddled up with parts bii) and biii)

For the first part, I've written this on my page but not sure if it's going anywhere correct;

L=i=1kciai L = \sum_{i=1}^k c_ia_i


L^=i=1kcia^i \hat{L} = \sum_{i=1}^k c_i\hat{a}_i

Unparseable latex formula:

\hat{a}_i = \bar{Y}_i_. - \bar{Y}_._.



Unparseable latex formula:

E(\hat{L}) = E(\sum_{i=1}^k c_i\hat{a}_i) = \sum_{i=1}^k c_iE((\bar{Y}_i_. - \bar{Y}_._.))



Then I'm a bit stuck.

Part biii) (I just want to check this is correct)

Unparseable latex formula:

Var(\bar{Y}_i_.) = Var (\frac{1}{n_i} \sum_{j = 1}^{n_i} Y_i_j)



Unparseable latex formula:

\frac{1}{n_i^2} \sum_{j = 1}^{n_i} Var( \mu + a_i + e_i_j)



=σ2ni =\frac{\sigma^2}{n_i}

Unparseable latex formula:

Var(\sum_{i = 1}^{k}c_i\bar{Y}_i_.) = \sigma^2 \sum_{i = 1}^{k} \frac{c_i^2}{n_i}



In this part, I've left out a lot of the steps I've written on the page to avoid typing it all out in latex but if there's any confusion, I can explain my logic.

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