Calculating Enthalpy Change

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  1. LukeyJB's Avatar
    • Exalted Member
    • Location: Leeds
    • Posts: 258
    Calculating Enthalpy Change
    6) Use your answer from question 5 (6.8) to calculate the heat given out during this experiment. Assume a density of 1.00gcm-³ and a specific heat capacity of 4.18.

    q=mc(Delta)T
    q= 1x4.18x6.8
    q=28.4/1000
    q=0.0284kjmol-1
    7) The HCl used in Task 1 had a concentration of 1.00moldm-³. Calculate the amount, in moles, of HCl present in the 25.0cm³ (0.025dm³) of this acid.

    1.00x0.025 = 0.025mol
    How would I do this question?

    8) Use your answers from questions 6 and 7 to calculate the enthalpy change, in kJmol-1, for the reaction between one mole of HCl and the glass cleaner.
  2. thegodofgod's Avatar
    • TSR Legend
    • Location: London
    • Posts: 10,878
    Re: Calculating Enthalpy Change
    (Original post by LukeyJB)
    How would I do this question?

    8) Use your answers from questions 6 and 7 to calculate the enthalpy change, in kJmol-1, for the reaction between one mole of HCl and the glass cleaner.
    Use the formula: \delta H = \frac{Q}{mol}

    \delta H = \frac{0.0284}{0.025}

    \delta H = 1.136 kJmol^{-1}

    Since heat is given out, the reaction is exothermic, and thus delta H is negative. Therefore, \delta H = -1.136 kJmol^{-1}
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