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    I am sort of stuck on this question. (exam- June 2009 question 11 part ii)

    The point P on the curve y=kX^0.5 has x-coordinate 4. the normal to the curve p is parallel to the line 2x+3y=0

    i) find the value k,

    I have found the value k and it is 6

    ii) this normal meets the x-axis at the point Q. calculate the area of the triangle OPQ. where o is the point (0,0)

    This is the part I am stuck on, I just don't know how to find the co-ordinate of Q.

    In the mark scheme the coordinates of Q are (22,0) but i have no idea how they have got this.

    Could some one please help me?
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    (Original post by unknown123)
    I am sort of stuck on this question. (exam- June 2009 question 11 part ii)

    The point P on the curve y=kX^0.5 has x-coordinate 4. the normal to the curve p is parallel to the line 2x+3y=0

    i) find the value k,

    I have found the value k and it is 6

    ii) this normal meets the x-axis at the point Q. calculate the area of the triangle OPQ. where o is the point (0,0)

    This is the part I am stuck on, I just don't know how to find the co-ordinate of Q.

    In the mark scheme the coordinates of Q are (22,0) but i have no idea how they have got this.

    Could some one please help me?
    Someone else also asked this question today, i have answered it on this thread.

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