C1 1 mark question! :(
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C1 1 mark question! :(
OCR Jun 10, Q8iii)
Here's the full question
i) express 2x^2 + 5x in the form 2(x+p)^2 + q
Answer: 2(x+ 5/4)^2 - 25/8
ii) State coords of the minimum points
(-5/4,-25/8)
PART THREE) State the equation of the normal to the curve at its minimum point..
So we know x coord of the minimum point is -5/4
How do work out the equation of normal? ( I know it should work out to be -1) so i assume the answer is 4/5? I dunno what am doing :P
..
Can you kindly guide me and if you do know the answer, can you tell me how you worked it Out
Thanks -
Re: C1 1 mark question! :(All that for one mark? I doubt that lol!(Original post by dongonaeatu)
equation of normal
is the perpendicular gradient of your tangent
and then you just slot the numbers in the formula y-y1-m(x-x1) where m is the gradient
Must be something else -
Re: C1 1 mark question! :(so you want to find out a gradient and you have(Original post by jameslad)
OCR Jun 10, Q8iii)
Here's the full question
i) express 2x^2 + 5x in the form 2(x+p)^2 + q
Answer: 2(x+ 5/4)^2 - 25/8
ii) State coords of the minimum points
(-5/4,-25/8)
PART THREE) State the equation of the normal to the curve at its minimum point..
So we know x coord of the minimum point is -5/4
How do work out the equation of normal? ( I know it should work out to be -1) so i assume the answer is 4/5? I dunno what am doing :P
..
Can you kindly guide me and if you do know the answer, can you tell me how you worked it Out
Thanks
(-5/4,-25/8)
so y2-y1/x2-x1 gives you the gradient of the tangent
you want the gradient of the normal which is perpendicular
can you do this -
Re: C1 1 mark question! :((Original post by jameslad)
OCR Jun 10, Q8iii)
Here's the full question
i) express 2x^2 + 5x in the form 2(x+p)^2 + q
Answer: 2(x+ 5/4)^2 - 25/8
ii) State coords of the minimum points
(-5/4,-25/8)
PART THREE) State the equation of the normal to the curve at its minimum point..
So we know x coord of the minimum point is -5/4
How do work out the equation of normal? ( I know it should work out to be -1) so i assume the answer is 4/5? I dunno what am doing :P
..
Can you kindly guide me and if you do know the answer, can you tell me how you worked it Out
Thanks
is the minimum point, see the graph, from the graph we can see that the equation of the normal will be
Last edited by raheem94; 11-05-2012 at 23:16. Reason: Mistake -
Re: C1 1 mark question! :(wont that be the normal?(Original post by raheem94)
is the minimum point, see the graph, from the graph we can see that the equation of the normal will be
oh sorry just notice the question asked for the normalLast edited by darkshadow1111; 11-05-2012 at 23:18. -
Re: C1 1 mark question! :(Well the normal is the perpendicular to the tangent.(Original post by jameslad)
OCR Jun 10, Q8iii)
Here's the full question
i) express 2x^2 + 5x in the form 2(x+p)^2 + q
Answer: 2(x+ 5/4)^2 - 25/8
ii) State coords of the minimum points
(-5/4,-25/8)
PART THREE) State the equation of the normal to the curve at its minimum point..
So we know x coord of the minimum point is -5/4
How do work out the equation of normal? ( I know it should work out to be -1) so i assume the answer is 4/5? I dunno what am doing :P
..
Can you kindly guide me and if you do know the answer, can you tell me how you worked it Out
Thanks
If it's a minimum point - what is the gradient of the tangent ALWAYS? -
Re: C1 1 mark question! :(Equation of tangent? It's asking for normal..(Original post by raheem94)
is the minimum point, see the graph, from the graph we can see that the equation of the tangent will be
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Re: C1 1 mark question! :(He meant normal.(Original post by jameslad)
Equation of tangent? It's asking for normal.. -
Re: C1 1 mark question! :(By mistake wrote tangent, i have corrected it.(Original post by jameslad)
Equation of tangent? It's asking for normal..
Sorry for the confusion it caused. -
Re: C1 1 mark question! :(minimum point- the gradient is positive is this right(Original post by hassi94)
Well the normal is the perpendicular to the tangent.
If it's a minimum point - what is the gradient of the tangent ALWAYS? -
Re: C1 1 mark question! :(Yes that's right so the tangent is just the horizontal line going through that point. Therefore the normal is the vertical line going through that point i.e. x = -5/4(Original post by jameslad)
zero? -
Re: C1 1 mark question! :(The gradient of the tangent is zero.(Original post by dongonaeatu)
so you want to find out a gradient and you have
(-5/4,-25/8)
so y2-y1/x2-x1 gives you the gradient of the tangent
you want the gradient of the normal which is perpendicular
can you do this
So for finding the gradient of the normal will we do
We can't do this here! -
Re: C1 1 mark question! :(No. How do we find minimum points using calculus?(Original post by dongonaeatu)
minimum point- the gradient is positive is this right
