Very annoying c1 question

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  1. IShouldBeRevising_'s Avatar
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    Very annoying c1 question


    It says in the mark scheme the coordinates for B = x, 11 - 2x

    I used x,y and tried working it out that way, I don't understand where they got 11 - 2x from?

    Oh actually I do get where they got it from they got it from the equation of the line, but how is that the y - coordinate?
    Last edited by IShouldBeRevising_; 12-05-2012 at 17:38.
  2. TenOfThem's Avatar
    • TSR Royalty
    Re: Very annoying c1 question
    (y-5) = -2(x-3)

    y - 5 = 6 - 2x
    y = 11 - 2x


    I cannot get that you understand this is the line but do not understand that it gives you y
  3. IShouldBeRevising_'s Avatar
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    Re: Very annoying c1 question
    (Original post by TenOfThem)
    (y-5) = -2(x-3)

    y - 5 = 6 - 2x
    y = 11 - 2x


    I cannot get that you understand this is the line but do not understand that it gives you y
    hmm don't know never come across such a question before
  4. raheem94's Avatar
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    Re: Very annoying c1 question
    (Original post by IShouldBeRevising_)


    It says in the mark scheme the coordinates for B = x, 11 - 2x

    I used x,y and tried working it out that way, I don't understand where they got 11 - 2x from?

    Oh actually I do get where they got it from they got it from the equation of the line, but how is that the y - coordinate?
    The equation of the line is  y=11-2x .

    Point B lies on this line, so its coordinates are  (x, 11-2x)

    We know the coordinates of A, so use the formula we use for finding the distance between 2 points.
  5. IShouldBeRevising_'s Avatar
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    Re: Very annoying c1 question
    (Original post by raheem94)
    The equation of the line is  y=11-2x .

    Point B lies on this line, so its coordinates are  (x, 11-2x)

    We know the coordinates of A, so use the formula we use for finding the distance between 2 points.
    Yeah I get the method, just didn't know why the y coordinate was 11-2x, but do now.

    Btw if you have a straight line with gradient 1 the tangent to this line has gradient -1, does the gradient of the normal to the line also = -1?
  6. TenOfThem's Avatar
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    Re: Very annoying c1 question
    (Original post by IShouldBeRevising_)
    Yeah I get the method, just didn't know why the y coordinate was 11-2x, but do now.

    Btw if you have a straight line with gradient 1 the tangent to this line has gradient -1, does the gradient of the normal to the line also = -1?
    If you have a straight line it can not have a tangent to it

    If you have a curve with gradient 1 at a given point then the tangent to the curve at that point also has gradient 1

    and the gradient of the normal would be -1
  7. raheem94's Avatar
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    Re: Very annoying c1 question
    (Original post by IShouldBeRevising_)
    Yeah I get the method, just didn't know why the y coordinate was 11-2x, but do now.

    Btw if you have a straight line with gradient 1 the tangent to this line has gradient -1, does the gradient of the normal to the line also = -1?
    Do we ever draw tangents to straight lines?
  8. JamieEclipse's Avatar
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    Re: Very annoying c1 question
    (Original post by IShouldBeRevising_)
    Btw if you have a straight line with gradient 1 the tangent to this line has gradient -1, does the gradient of the normal to the line also = -1?
    The gradient of the normal would be -1.

    If you did figure out a tangent to a straight line it would have the same gradient as the line. However, tangent to a straight line = straight line so you'd never need to figure that out.
  9. IShouldBeRevising_'s Avatar
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    Re: Very annoying c1 question
    (Original post by TenOfThem)
    If you have a straight line it can not have a tangent to it

    If you have a curve with gradient 1 at a given point then the tangent to the curve at that point also has gradient 1

    and the gradient of the normal would be -1

    (Original post by raheem94)
    Do we ever draw tangents to straight lines?

    (Original post by JamieEclipse)
    The gradient of the normal would be -1.

    If you did figure out a tangent to a straight line it would have the same gradient as the line. However, tangent to a straight line = straight line so you'd never need to figure that out.
    Yeah just got confused thanks for the help, very speedy service :P
  10. bong's Avatar
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    Re: Very annoying c1 question
    (Original post by IShouldBeRevising_)
    Yeah just got confused thanks for the help, very speedy service :P
    Is the answer (9,-7) and (-3,17) ?
  11. IShouldBeRevising_'s Avatar
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    Re: Very annoying c1 question
    (Original post by bong)
    Is the answer (9,-7) and (-3,17) ?
    Nope
  12. masterhr1's Avatar
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    Re: Very annoying c1 question
    lol C1. Those were the days...
  13. IShouldBeRevising_'s Avatar
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    Re: Very annoying c1 question
    (Original post by masterhr1)
    lol C1. Those were the days...
    lol why what you doing?
  14. Buongiorno's Avatar
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    Re: Very annoying c1 question
    What paper is this question from?
  15. IShouldBeRevising_'s Avatar
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    Re: Very annoying c1 question
    (Original post by Buongiorno)
    What paper is this question from?
    January 2012
  16. Buongiorno's Avatar
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    Re: Very annoying c1 question
    (Original post by IShouldBeRevising_)
    January 2012
    Thanks. Edexcel or another exam board?
  17. Pride's Avatar
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    Re: Very annoying c1 question
    aww man I can't do this one...

    can anybody help here?

    oh actually. I've got an idea, give me a sec.
    Last edited by Pride; 12-05-2012 at 20:21.
  18. IAmMclovin's Avatar
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    Re: Very annoying c1 question
    what were the answers, i got (9,-7) and (-3,17) by setting up a circle centre (3,5) of radius 6root5, and then i sub y=-2x+11 into

    (x-3)^2 = (y-5)^2 = 180 to equate the lines and then solved?
    Last edited by IAmMclovin; 12-05-2012 at 20:39.
  19. IAmMclovin's Avatar
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    Re: Very annoying c1 question
    (Original post by Pride)
    aww man I can't do this one...

    can anybody help here?
    I checked my answer and this seems right: set up a circle centre A(3,5) with radius 6root5 to get formula (x-3)^2 +(y-5)^2 = 180, then sub in y=-2x +11 to solve
  20. Pride's Avatar
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    Re: Very annoying c1 question
    (Original post by IAmMclovin)
    what were the answers, i got (9,-3) and (-7,17) by setting up a circle centre (3,5) of radius 6root5, and then i sub y=-2x+11 into

    (x-3)^2 = (y-5)^2 = 180 to equate the lines and then solved?
    yeah, when you draw it, it's a lot easier to see that it's a circle.
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