Rate of change of circle inside a square (difficult)

Maths and statistics discussion, revision, exam and homework help.

Announcements Posted on
Please change your TSR password 23-05-2013
Enter our travel-writing competition for the chance to win a Nikon 1 J3 camera 20-05-2013
IMPORTANT: You must wait until midnight (morning exams)/4.30AM (afternoon exams) to discuss Edexcel exams and until 1pm/6pm the following day for STEP and IB exams. Please read before posting, including for rules for practical and oral exams. 28-04-2013
Sign in to Reply
  1. Extricated's Avatar
    • Overlord in Training
    • Posts: 2,661
    Rate of change of circle inside a square (difficult)
    Hi guys, I came across this question and just need a little push I think..

    If we have a circle inside a square so that the sides of the square lie tangent to the circle, find the rate of change of the perimeter of the square if the rate of change of the circumference of the circle is 6ms^-1.

    I've tried to write the circumference as 2pi*r

    so d/dt (2pi*r) = 6 which obviously isn't right, maybe i'm just not thinking straight..any ideas??
  2. ztibor's Avatar
    • Peer Of The TSR Realm
    • Location: Hungary
    • Posts: 1,540
    Re: Rate of change of circle inside a square (difficult)
    (Original post by Extricated)
    Hi guys, I came across this question and just need a little push I think..

    If we have a circle inside a square so that the sides of the square lie tangent to the circle, find the rate of change of the perimeter of the square if the rate of change of the circumference of the circle is 6ms^-1.

    I've tried to write the circumference as 2pi*r

    so d/dt (2pi*r) = 6 which obviously isn't right, maybe i'm just not thinking straight..any ideas??
    SO the rate of r
    d/dt(r)=6/(2pi)
    The perimeter of the square is 4r
  3. JonathanM's Avatar
    • Full Member
    • Posts: 100
    Re: Rate of change of circle inside a square (difficult)
    You know it helps to state what topic it is.

    You should use connected rates of change.

    Label the length of the sides of the square x and the rest should be pretty obvious.

    ztibor you didn't do anything lol.

    So you have the circumference of the circle

    6ms^-1 = dC/dt (C= circumference)

    Therefore dP/dt = dP/dC *dC/dt
    P = Perimeter of square.
    Last edited by JonathanM; 12-05-2012 at 23:29.
  4. Intriguing Alias's Avatar
    • TSR Idol
    • Location: Yorkshire
    Re: Rate of change of circle inside a square (difficult)
    (Original post by JonathanM)
    You know it helps to state what topic it is.

    You should use connected rates of change.

    Label the length of the sides of the square x and the rest should be pretty obvious.

    ztibor you didn't do anything lol.
    Ztibor has essentially solved the problem so I don't know what you're talking about.

    (Except he should've wrote that the perimeter of the square is 8r, I believe).
  5. JonathanM's Avatar
    • Full Member
    • Posts: 100
    Re: Rate of change of circle inside a square (difficult)
    (Original post by hassi94)
    Ztibor has essentially solved the problem so I don't know what you're talking about.

    (Except he should've wrote that the perimeter of the square is 8r, I believe).
    How has he solved it? I can't see how he got from "d/dt(r)=6/(2pi)
    to "The perimeter of the square is 4r".
  6. Intriguing Alias's Avatar
    • TSR Idol
    • Location: Yorkshire
    Re: Rate of change of circle inside a square (difficult)
    (Original post by JonathanM)
    How has he solved it? I can't see how he got from "d/dt(r)=6/(2pi)
    to "The perimeter of the square is 4r".
    He didn't get from one to the other. He got to the first bit, then gave the second bit of information (which okay was wrong but it's easy to make mistakes) and then left the OP to do the simple last bit.
    Last edited by Intriguing Alias; 12-05-2012 at 23:29.
  7. JonathanM's Avatar
    • Full Member
    • Posts: 100
    Re: Rate of change of circle inside a square (difficult)
    (Original post by hassi94)
    He didn't get from one to the other. He got to the first bit, then gave the second bit of information (which okay was wrong but it's easy to make mistakes) and then left the OP to do the simple last bit.
    I don't think the OP understands the question. I understand what the hungarian guy meant now it's just the fact I mistook what he said. And what he said has no relevance to how you solve it anyway. Only the 4r bit. Top tip for him, a length of a side of a square isn't the radius.

    dC/dt = 6

    Perimeter = 4x
    Circumference = root(2)*pi*x
    P = 4(C/pi*root(2))
    dP/dC = 4/(pi*root(2))

    dP/dt = 24/pi*root(2)
    Last edited by JonathanM; 12-05-2012 at 23:45.
  8. Intriguing Alias's Avatar
    • TSR Idol
    • Location: Yorkshire
    Re: Rate of change of circle inside a square (difficult)
    (Original post by JonathanM)
    I don't think the OP understands the question. I understand what the hungarian guy meant now it's just the fact I mistook what he said. And what he said has no relevance to how you solve it anyway. Only the 4r bit.
    Wow I don't think you're getting this. It has absolute relevance.

    If d/dt (2pi r) = 6 then d/dt (r) = 6/2pi = 3/pi

    And you can logically work out that the square must be of side 2r and so the perimeter is 8r.

    Then we can write d/dt(8r) = 24/pi

    Now if there's something wrong there, tell me. Otherwise stop commenting that something is wrong or irrelevant just because you don't understand how it's relevant.
  9. Intriguing Alias's Avatar
    • TSR Idol
    • Location: Yorkshire
    Re: Rate of change of circle inside a square (difficult)
    (Original post by JonathanM)
    I don't think the OP understands the question. I understand what the hungarian guy meant now it's just the fact I mistook what he said. And what he said has no relevance to how you solve it anyway. Only the 4r bit. Top tip for him, a length of a side of a square isn't the radius.

    dC/dt = 6

    Perimeter = 4x
    Circumference = root(2)*pi*x
    P = 4(C/pi*root(2))
    dP/dC = 4/(pi*root(2))

    dP/dt = 24/pi*root(2)
    Where in the world has root(2) come from?
  10. JonathanM's Avatar
    • Full Member
    • Posts: 100
    Re: Rate of change of circle inside a square (difficult)
    You're answer is wrong the r for the circle is not the same as the r (length of a side) for a square.

    Using chain rule I got dP/dt = 24/pi*root(2)
  11. Extricated's Avatar
    • Overlord in Training
    • Posts: 2,661
    Re: Rate of change of circle inside a square (difficult)
    (Original post by hassi94)
    Where in the world has root(2) come from?

    (Original post by ztibor)
    SO the rate of r
    d/dt(r)=6/(2pi)
    The perimeter of the square is 4r
    Thanks guys




    (Original post by JonathanM)
    I don't think the OP understands the question. I understand what the hungarian guy meant now it's just the fact I mistook what he said. And what he said has no relevance to how you solve it anyway. Only the 4r bit. Top tip for him, a length of a side of a square isn't the radius.

    dC/dt = 6

    Perimeter = 4x
    Circumference = root(2)*pi*x
    P = 4(C/pi*root(2))
    dP/dC = 4/(pi*root(2))

    dP/dt = 24/pi*root(2)

    lol, it's actually ironic that the only bit that ztibor got wrong (i.e the 4r bit) is what you're claiming is the only bit he's got right
    Last edited by Extricated; 12-05-2012 at 23:48.
  12. F1Addict's Avatar
    • Peer Of The TSR Realm
    • Posts: 1,744
    Re: Rate of change of circle inside a square (difficult)
    (Original post by JonathanM)
    You're answer is wrong the r for the circle is not the same as the r (length of a side) for a square.
    Yeah it isn't r. Its 2r. In words, the length of a side of a square is 2 times the radius of the circle within the square.
  13. JonathanM's Avatar
    • Full Member
    • Posts: 100
    Re: Rate of change of circle inside a square (difficult)
    (Original post by Extricated)

    lol, it's actually ironic that the only bit that ztibor got wrong (i.e the 4r bit) is what you're claiming is the only bit he's got right
    Well by that I meant if he meant r as a length of the side of the square, not the radius of the circle.
  14. Venomilys's Avatar
    • Overlord in Training
    • Posts: 2,311
    Re: Rate of change of circle inside a square (difficult)
    (Original post by JonathanM)
    Top tip for him, a length of a side of a square isn't the radius.

    dC/dt = 6

    Perimeter = 4x
    Circumference = root(2)*pi*x
    P = 4(C/pi*root(2))
    dP/dC = 4/(pi*root(2))

    dP/dt = 24/pi*root(2)
    I think you need more help than the OP.
  15. steve2005's Avatar
    • TSR Demigod
    • Location: LONDON
    Re: Rate of change of circle inside a square (difficult)
    (Original post by JonathanM)
    Well by that I meant if he meant r as a length of the side of the square, not the radius of the circle.
    LOL:confused:
  16. Intriguing Alias's Avatar
    • TSR Idol
    • Location: Yorkshire
    Re: Rate of change of circle inside a square (difficult)
    (Original post by JonathanM)
    You're answer is wrong the r for the circle is not the same as the r (length of a side) for a square.

    Using chain rule I got dP/dt = 24/pi*root(2)
    Look if you've set the perimeter to = 4x then each side = x.


    Each side is the diameter of the circle and since circumference = pi*diameter then C = pi*x with no root(2)
  17. JonathanM's Avatar
    • Full Member
    • Posts: 100
    Re: Rate of change of circle inside a square (difficult)
    (Original post by F1Addict)
    Yeah it isn't r. Its 2r. In words, the length of a side of a square is 2 times the radius of the circle within the square.

    Urm what?
    Click image for larger version. 

Name:	a76b64967e6a404185e953b.png 
Views:	40 
Size:	3.6 KB 
ID:	147428
  18. Intriguing Alias's Avatar
    • TSR Idol
    • Location: Yorkshire
    Re: Rate of change of circle inside a square (difficult)
    (Original post by JonathanM)
    Well by that I meant if he meant r as a length of the side of the square, not the radius of the circle.
    "I've tried to write the circumference as 2pi*r"


    :lolwut:
  19. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: Rate of change of circle inside a square (difficult)
    (Original post by Ilyas)
    ...
    I have uploaded the file you requested, here is the link to it.

    Sorry for posting it here, but i saw that you had blocked visitor messages.
  20. Intriguing Alias's Avatar
    • TSR Idol
    • Location: Yorkshire
    Re: Rate of change of circle inside a square (difficult)
    (Original post by JonathanM)
    Urm what?
    Click image for larger version. 

Name:	a76b64967e6a404185e953b.png 
Views:	40 
Size:	3.6 KB 
ID:	147428
    Okay yeah you've understood this completely incorrectly.

    Original Post:

    "we have a circle inside a square so that the sides of the square lie tangent to the circle"
Sign in to Reply
Share this discussion:  
Article updates
Moderators

We have a brilliant team of more than 60 volunteers looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

Reputation gems:
The Reputation gems seen here indicate how well reputed the user is, red gem indicate negative reputation and green indicates a good rep.
Post rating score:
These scores show if a post has been positively or negatively rated by our members.