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Double Integrals
Can anyone explain to me how to put the function
I = R∫∫x^2 + y^2 dxdy as a repeated integral when R is the region bounded by the straight lines x=1, y=1 and x + y =1
I've got
I= 0 to 1∫dx x to 1∫x^2 + y^2 dy
I'm not sure if I have done this correct and would appreciate it if anybody can explain this to me.
Thanks
I = R∫∫x^2 + y^2 dxdy as a repeated integral when R is the region bounded by the straight lines x=1, y=1 and x + y =1
I've got
I= 0 to 1∫dx x to 1∫x^2 + y^2 dy
I'm not sure if I have done this correct and would appreciate it if anybody can explain this to me.
Thanks
I then evaluated this to 1/4
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