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Maximum of the function F(X)=X*(1+X)^0.5

Hello,
Is x=-1 local maximum of F(x)=x1+x F(x)=x\sqrt{1+x}
On the one hand, F(1+δ)<F(1) F(-1+\delta)<F(-1) for 0<δ<1 0<\delta<1.
However, F(1δ) F(-1-\delta) is not defined.
As far a I know, the point x=a is considered local maximum, if there exists small neighborhood δ \delta such that F(a)>F(x) F(a)>F(x) for every aδ<x<a+δ a-\delta<x<a+\delta.

So is x=-1 a local maximum or not?
Reply 1
Original post by msokol
Hello,
Is x=-1 local maximum of F(x)=x1+x F(x)=x\sqrt{1+x}
On the one hand, F(1+δ)<F(1) F(-1+\delta)<F(-1) for 0<δ<1 0<\delta<1.
However, F(1δ) F(-1-\delta) is not defined.
As far a I know, the point x=a is considered local maximum, if there exists small neighborhood δ \delta such that F(a)>F(x) F(a)>F(x) for every aδ<x<a+δ a-\delta<x<a+\delta.

So is x=-1 a local maximum or not?


Since the function is not defined for values < -1 you consider -1 as endpoint of the interval your function is defined on. If the function takes a value at -1 which is greater than for other values (which the function is defined for) in a neighbourhood of -1, then -1 is a maximum.

This is what you stated above, so yes, -1 is a local maximum.

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