[bossman42]

Yeahhh thats what I got, but someone earlier put the signs the other way around so I was baffled

[George_]

I thought it was really easy compared to other Core 1 exams in the past.

[genius017]

What was the answer to the last question?
you had to draw the quadratic cruve and write down the coordinates of the roots?????

[Axion]

(Original post by superduperr)
no dont think so...

why? First I multiplied the left by 3/2. Then transferred the c across, then squared rooted it ? ?

[alex7892]

I sware it was -5<k<5 not square root of it?

Does anyone remember the question/numbers?

[George_]

(Original post by Axion)
why? First I multiplied the left by 3/2. Then transferred the c across, then squared rooted it ? ?

Yeah, you should have got 3a/2c all square rooted.

I certainly did

[GreenLantern1]

(Original post by abdus110)
no ppl it is -20 whetever question u on about cause i checked it on my graphics calculator afterwards and askd the teacher that 2x-5 whatever is crap

You obviously didn't ask your teacher as for him to tell you that is utter crap

[henshin]

Oh God can someone please tell me if I've failed, for that graph question i didn't know you had to multiply by 2. I got y = (x+1/2)(x+2)(x-5) and then I carried on using that for all the next questions, so my graph had intercept at -5, and I got -20 for that new intercept question instead of -40 Isn't that like a dozen or more marks gone? Also for the translation by 3 units to right I got (x-2.5)(x-1)(x-8). I really need some consolation please

[bossman42]

(Original post by genius017)
What was the answer to the last question?
you had to draw the quadratic cruve and write down the coordinates of the roots?????

I got something like

3/2 + root5 /2 and
3/2 - root5 /2

[GreenLantern1]

(Original post by Axion)
why? First I multiplied the left by 3/2. Then transferred the c across, then squared rooted it ? ?

What was the original formula again?

[George_]

(Original post by alex7892)
I sware it was -5<k<5 not square root of it?

Does anyone remember the question/numbers?

It was 4k^2 - 20 < 0

4k^2 < 20
k^2 < 5
k < +/-root 5



Then turn that into an equality, that's how I did it. I confused myself though because I had k as both less than + and - root 5, so I rearranged a bit to try and get an actual answer, ending up at -root5 < k < root5

[Axion]

(Original post by superduperr)
omg that is annoying! why didnt i see that :'(

2/3 x 3/2 is 1 therefore surely mine and alloties answers are correct?

[Alotties]

(Original post by henshin)
Oh God can someone please tell me if I've failed, for that graph question i didn't know you had to multiply by 2. I got y = (x+1/2)(x+2)(x-5) and then I carried on using that for all the next questions, so my graph had intercept at -5, and I got -20 for that new intercept question instead of -40 Isn't that like a dozen or more marks gone? Also for the translation by 3 units to right I got (x-2.5)(x-1)(x-8). I really need some consolation please

You may have got error carried forward for your results, so lost most marks on the first one but as long as you use the numbers you got correctly you can still pick up marks. I hope you did, good luck

[George_]

(Original post by GreenLantern1)
What was the original formula again?

a = 2/3b^2c

[Axion]

(Original post by George_)
It was 4k^2 - 20 < 0

4k^2 < 20
k^2 < 5
k < +/-root 5



Then turn that into an equality, that's how I did it. I confused myself though because I had k as both less than + and - root 5, so I rearranged a bit to try and get an actual answer, ending up at -root5 < k < root5

lol complete flop then

[George_]

(Original post by Axion)
2/3 x 3/2 is 1 therefore surely mine and alloties answers are correct?

No, you divide a by 2/3 thirds, which is the same as multiplying a by 3/2. You don't multiply the fractions together.

[George_]

(Original post by Axion)
lol complete flop then

I'm sure you did fine!

[Alotties]

a = 2/3b^2c

3a = 2b^2c
3a/2 = b^2c
3a/2/c = b^2 which is rearranged to 3ac/2
so b = squareroot of 3ac/2

[Axion]

(Original post by George_)
No, you divide a by 2/3 thirds, which is the same as multiplying a by 3/2. You don't multiply the fractions together.

To get rid of 2/3 on one side you times the other by 3/2 ,no?

[getenoughsuarez]

Can someone start an unofficial mark scheme and everyone adds to it?

Thanks also for the -root5<k<root5 question how many marks would I lose if I wrote root5<K and -root5>K