C1 MEI Wednesday 16th May 2012
Maths exam discussion - share revision tips in preparation for GCSE, A Level and other maths exams and discuss how they went afterwards.
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Re: C1 MEI Wednesday 16th May 2012
(6x+9)/5 < (5x+7)/6
36x + 54 < 25x + 35 (so on this line the left side has been times by 6 and the right side has been times by 5)
36x < 25x + 35 - 54
36x + 25x < -19
11x < -19
x < -19/11
I multiply each side by the opposite denominator and go from there
I find it easiest as you don't get the biggest numbers ever as you would if you maybe multiplied by a common denominator.
(If this is wrong, I apologise
)
(Original post by alex7892)
Hi guys got this exam tommorow aswell. Was doing a past paper and does anyone know how to solve an inequality like this (random example btw) :
6x+9 5x+7
----- < --------
5 6
the dotted line refers to it being divided, thanks everyoneeee!!Last edited by Alotties; 15-05-2012 at 18:17. -
Re: C1 MEI Wednesday 16th May 2012Thanks for this, alot of help!!! Will be on tommorow after the exam, so we can discuss!(Original post by Alotties)
(6x+9)/5 < (5x+7)/6
36x + 54 < 25x + 35
36x < 25x + 35 - 54
36x + 25x < -19
11x < -19
x < -19/11
I multiply each side by the opposite denominator and go from there
I find it easiest as you don't get the biggest numbers ever as you would if you maybe multiplied by a common denominator.
(If this is wrong, I apologise
)
Anyone have any specific tips? -
Re: C1 MEI Wednesday 16th May 2012
My tips:
1) Answer all the questions you find easiest on section A first to get the easy marks, then do the parts you understand from section B, after this go back to the harder section A questions and then go back to the difficult section B parts at the end. This is incase you run out of time so at least you've maximised the marks you are able to get.
2) Take a pencil and rubber in so that if you are unsure about some working out you can do it in pencil first and then write it in pen so that you aren't wasting space or forgetting to cross working out.
3) Don't panic!
I can't think of any others atm!
What grade are you aiming for?
(Original post by alex7892)
Thanks for this, alot of help!!! Will be on tommorow after the exam, so we can discuss!
Anyone have any specific tips? -
Re: C1 MEI Wednesday 16th May 2012I'm aiming for a high A seeing as I got a B in Jan(Original post by alex7892)
Well I'm just aiming for an A. Feel more confident in stats and C2. I found this with chemistry aswell, more confident in unit 2 than 1 haha. Should be okay though, just going to revise hard tonight and maybe repeat a few past papers!
In some years my B would have been an A
Silly boundaries!
I am pretty confident with C2 (but I do need to revisit it as I haven't covered it for a while) and I'm getting better with S1!
I am very scared of Unit 2 Chem! What board are you on? -
Re: C1 MEI Wednesday 16th May 2012Hi! I honestly don't know how I got 78! Although lots of people seem to get 100 UMS on C1.(Original post by Salvatore8)
Anymore ideas on what could come up?
and just to ask, how did you get 78 first time round?
I think it's pretty much guaranteed that the following will come up:
Surds
Binomial expansion/Coefficient of x^y
Cubic equations-Sketching the graph of, finding the roots of, finding remainder when dividing by an expression.
Rearranging equations
Circles
I hope the 'implying' questions don't crop up again- they confuse me
Hope it goes well for you tomorrow! -
Re: C1 MEI Wednesday 16th May 2012
hi i need a lot of help with this question 11 on this paper http://www.mei.org.uk/files/papers/c107ja_3hoza9.pdf
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Re: C1 MEI Wednesday 16th May 2012For 11A.(Original post by King of the Jungle)
hi i need a lot of help with this question 11 on this paper http://www.mei.org.uk/files/papers/c107ja_3hoza9.pdf
Just read off on the y axis y=4 and write down x coordinates of intersections.
For 11B
Draw the line -x +4 = y -
Re: C1 MEI Wednesday 16th May 2012(Original post by AspiringGenius)
Can you help me with factor or remainder theorum please? Its the only thing I haven't really learnt properly. I'm trying to teach myself now but we didn't go over it in class.
My question is from June 2010 paper, using factor theorum,
f(x)=x^3 + 6x^2 - x - 30. Using factor theorum find a root of f(x)=0 and factorise completely.
Now I can factorise completely, and by observation I can tell that x=2 is a root of this polynomial. This means the fully factorised version becomes f(x)=(x-2)(x+3)(x+5), but as this is all by observation, I am prettty certain I'd lose all the marks.
How wuld you go about this?
Ok, sorry if someone has already explained this to you.
By observation you have found that x=2 is a root, therefore you can state that (x-2) is a factor of f(x)=0
At this stage, whilst some would do division, I would adopt a more algebraic approach (probably because the division method blags my head!):
(x-2)(x^2+Bx+C)=x^3+6x^2-x-30
Multiplying these brackets gives:
x^3+Bx^2+Cx-2x^2-2Bx-2C
Which can be expressed as:
x^3+(B-2)x^2+(C-2B)x-2C
So x^3+(B-2)x^2+(C-2B)x-2C=x^3+6x^2-x-30
(B-2)=6 therefore B=8
(C-2B)=-1 therefore C=15
We can now plug these values of B and C into the identity (x^2+Bx+C) to give:
(x-2)(x^2+8x+15)
By inspection, (x^2+8x+15) can be factorised to (x+3)(x+5).
This gives the full factorisation of (x-2)(x+3)(x+5)
Hope that helps! -
Re: C1 MEI Wednesday 16th May 2012Haha oh fair, I'm sure you will do well and we can all talk about this tommorow. I am on AQA what about you?(Original post by Alotties)
I'm aiming for a high A seeing as I got a B in Jan
In some years my B would have been an A
Silly boundaries!
I am pretty confident with C2 (but I do need to revisit it as I haven't covered it for a while) and I'm getting better with S1!
I am very scared of Unit 2 Chem! What board are you on? -
Re: C1 MEI Wednesday 16th May 2012thanks, but I already knew the answers, ti was just clarity of working I was concerned about.(Original post by jordan95)
Ok, sorry if someone has already explained this to you.
By observation you have found that x=2 is a root, therefore you can state that (x-2) is a factor of f(x)=0
At this stage, whilst some would do division, I would adopt a more algebraic approach (probably because the division method blags my head!):
(x-2)(x^2+Bx+C)=x^3+6x^2-x-30
Multiplying these brackets gives:
x^3+Bx^2+Cx-2x^2-2Bx-2C
Which can be expressed as:
x^3+(B-2)x^2+(C-2B)x-2C
So x^3+(B-2)x^2+(C-2B)x-2C=x^3+6x^2-x-30
(B-2)=6 therefore B=8
(C-2B)=-1 therefore C=15
We can now plug these values of B and C into the identity (x^2+Bx+C) to give:
(x-2)(x^2+8x+15)
By inspection, (x^2+8x+15) can be factorised to (x+3)(x+5).
This gives the full factorisation of (x-2)(x+3)(x+5)
Hope that helps!
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Re: C1 MEI Wednesday 16th May 2012They don't.(Original post by jordan95)
Hi! I honestly don't know how I got 78! Although lots of people seem to get 100 UMS on C1.
I think it's pretty much guaranteed that the following will come up:
Surds
Binomial expansion/Coefficient of x^y
Cubic equations-Sketching the graph of, finding the roots of, finding remainder when dividing by an expression.
Rearranging equations
Circles
I hope the 'implying' questions don't crop up again- they confuse me
Hope it goes well for you tomorrow!
Cumbersome method.(Original post by jordan95)
Ok, sorry if someone has already explained this to you.
By observation you have found that x=2 is a root, therefore you can state that (x-2) is a factor of f(x)=0
At this stage, whilst some would do division, I would adopt a more algebraic approach (probably because the division method blags my head!):
(x-2)(x^2+Bx+C)=x^3+6x^2-x-30
Multiplying these brackets gives:
x^3+Bx^2+Cx-2x^2-2Bx-2C
Which can be expressed as:
x^3+(B-2)x^2+(C-2B)x-2C
So x^3+(B-2)x^2+(C-2B)x-2C=x^3+6x^2-x-30
(B-2)=6 therefore B=8
(C-2B)=-1 therefore C=15
We can now plug these values of B and C into the identity (x^2+Bx+C) to give:
(x-2)(x^2+8x+15)
By inspection, (x^2+8x+15) can be factorised to (x+3)(x+5).
This gives the full factorisation of (x-2)(x+3)(x+5)
Hope that helps! -
Re: C1 MEI Wednesday 16th May 2012Wait..(Original post by jordan95)
Hi! I honestly don't know how I got 78! Although lots of people seem to get 100 UMS on C1.
I think it's pretty much guaranteed that the following will come up:
Surds
Binomial expansion/Coefficient of x^y
Cubic equations-Sketching the graph of, finding the roots of, finding remainder when dividing by an expression.
Rearranging equations
Circles
I hope the 'implying' questions don't crop up again- they confuse me
Hope it goes well for you tomorrow!
That sounds like C2?
Are you sure about that coming up on C1
Thanks for the Luck! much of it is needed
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Re: C1 MEI Wednesday 16th May 2012i see ya trollin', I hatin'
(jokes, I can't hate anybody, well done!)
That is C1 I'm afraid, are you with the right exam board?(Original post by Salvatore8)
Wait..
That sounds like C2?
Are you sure about that coming up on C1
Thanks for the Luck! much of it is needed
We have:
-basic algebra
-coordinate geometry
-polynomials (including binomial expansion)
-surds and indicies
-uncertainty
-language of mathematic (fun fun fun!)
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Re: C1 MEI Wednesday 16th May 2012I always find even if something is slightly cumbersome, it's best to do because they specifically state on the paper that answers without sufficient working may not gain marks, so it's always best to be safe and not miss out any potential mark awarding steps(Original post by jordan95)
It may be a 'cumbersome' method, but it's the one to which I afford preference. In fact, I wouldn't even call it cumbersome, when it takes all of a minute to complete. -
Re: C1 MEI Wednesday 16th May 2012Now that you Mention it.. I dont think i am?(Original post by AspiringGenius)
i see ya trollin', I hatin'
(jokes, I can't hate anybody, well done!)
That is C1 I'm afraid, are you with the right exam board?
We have:
-basic algebra
-coordinate geometry
-polynomials (including binomial expansion)
-surds and indicies
-uncertainty
-language of mathematic (fun fun fun!)
What Exam Board is this?
WOW.... You Nearly Gave Me a Heart attack! Phew


Silly boundaries!