m1 vector question

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  1. examweek's Avatar
    • New Member
    • Posts: 3
    m1 vector question
    d^2 = 25t^2 - 112t +169

    find the length of time to the nearest minute for which the distance is less than 11km
  2. steve2005's Avatar
    • TSR Demigod
    • Location: LONDON
    Re: m1 vector question
    (Original post by examweek)
    d^2 = 25t^2 - 112t +169

    find the length of time to the nearest minute for which the distance is less than 11km
    d^2=121

    Form a quadratic and factorise .
  3. raheem94's Avatar
    • TSR Demigod
    • Posts: 5,512
    Re: m1 vector question
    (Original post by examweek)
    d^2 = 25t^2 - 112t +169

    find the length of time to the nearest minute for which the distance is less than 11km
     11^2 > 25t^2 -112t +169 \implies 0> 25t^2 -112t +48 \implies 25t^2 -112t +48 < 0

    Now find the critical values by solving,  25t^2 -112t +48 = 0

    At the end draw the graph, and find the required length of time.
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