AQA Physics A - PHYA4 (11/06/12) - Exam thread
Physics exam discussion - share revision tips in preparation for GCSE, A Level and other physics exams and discuss how they went afterwards.
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Re: AQA Physics A - PHYA4 (11/06/12) - Exam thread
paul, for 11, im not sure how to do it calculation wise. but i just used logic. 24 hours is us now. So its not that. 160 hours is too long. 4.5x10^-2 would be too short. so by process of elimination i would go for 1.4 hours. But if you find out how to do it please let me know
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Re: AQA Physics A - PHYA4 (11/06/12) - Exam threadyou need a 90% average in the A2 modules and an A grade overall - not 90% in each module.(Original post by FrightBright)
Hey guys I got less than 90% in my ISA. My teacher says I cannot get an A* because I need 90% + in all 3 units seperately..
Is he mistaken? I mean surely if I get 90% overall I get an A*.
Can someone confirm thanks. -
Re: AQA Physics A - PHYA4 (11/06/12) - Exam threadDo you know where I can find these legacy papers?(Original post by swert)
can some please help me on this question im stuck on its from a legacy paper june 2007 question 9. I dont even know how to approach it :/
Cheers. -
Re: AQA Physics A - PHYA4 (11/06/12) - Exam threadhttp://www.freeexampapers.com/past_p...A%2FPhysics+A/
here knock yourself out oh if do mange to solve the question i was on about do let me know how to do it
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Re: AQA Physics A - PHYA4 (11/06/12) - Exam threadwhat? are you saying that you just get rid of the m in mrw^2? if mg is zero (the weight) then mrw^2 will equal zero..(Original post by don'tTRIP.)
The keyword here is 'weight'.
Rearrange mg = mrw^2 and there's your answer
To the guy asking about question 11, 21 and 22
I'm quite unsure about the quesiton 21, i don't think a flux linkage can decrease? as long as it is being turned flux linkage/emf will be induced, and the question doesn't state whether the emf is positive or not
someone help me out here !
edit : Q 11 was B, the guy who did it by common sense got it right
21 is B, the flux linkage increases. unless they gave you a value for the emf (which they wont in these questions) then it will increase
22 is D, 9 x 10-1 (0.9) - did by (150 x 10 x 60) area x b fieldLast edited by callmenighthawk; 03-06-2012 at 15:15. -
Re: AQA Physics A - PHYA4 (11/06/12) - Exam threadFirst you cancel out the m's so your left with g = rw^2(Original post by callmenighthawk)
what? are you saying that you just get rid of the m in mrw^2? if mg is zero (the weight) then mrw^2 will equal zero..
To the guy asking about question 11, 21 and 22
I'm quite unsure about the quesiton 21, i don't think a flux linkage can decrease? as long as it is being turned flux linkage/emf will be induced, and the question doesn't state whether the emf is positive or not
someone help me out here !
Then you have g = r(2pi/T)^2
Rearrange to get t on it's own; this is in seconds
Divide your answer by 3600 to get it into hours and bazinga
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Re: AQA Physics A - PHYA4 (11/06/12) - Exam threadthanks man.(Original post by don'tTRIP.)
First you cancel out the m's so your left with g = rw^2
Then you have g = r(2pi/T)^2
Rearrange to get t on it's own; this is in seconds
Divide your answer by 3600 to get it into hours and bazinga
anyone else finding the student room threads on exams to be very helpful? points out where you don't know certain methods/understanding of a subject rather than the physics itself, I feel like all of us can do the physics it's just the communication/looking at the question in the right way. -
Re: AQA Physics A - PHYA4 (11/06/12) - Exam threadthat is very difficult, you're on about the capacitors one?(Original post by swert)
http://www.freeexampapers.com/past_p...A%2FPhysics+A/
here knock yourself out oh if do mange to solve the question i was on about do let me know how to do it
I tried this : V = Vo e^-t/rc
ln (1/2) / 0.035 = constant (RC)
then did ln (1/16) x constant(rc) to get a time of 54 seconds lolz
it's clearly C or D but I can't do the math..
ok i've rearranged wrong it should be RC = 0.035 / ln 1/2
still getting a answer not on the scheme
wow that is a tough question I think I worked it out
E = 1/2 QV when Q halves then V halves
when e = 1/16 it must equal 0.5 x charge x voltage
1/16 / 0.5 square rooted = 0.35 volts
to find RC you do 0.035 / ln (1/2) to get 0.05 or something
then you do ln (0.35 / 1) x 0.05 to get 51ms, apparently it isn't either C or D if what I did was right
surely they don't expect you to do all that for one mark?Last edited by callmenighthawk; 03-06-2012 at 16:26. -
Re: AQA Physics A - PHYA4 (11/06/12) - Exam threadThanks capacitance is constant.(Original post by swert)
http://www.freeexampapers.com/past_p...A%2FPhysics+A/
here knock yourself out oh if do mange to solve the question i was on about do let me know how to do it
Half life is 36ms.
Energy strored is 1/2(Q)(V^2)
So you want the voltage to drop to 1/4(V) because when you square it it's 1/16.
So just 36x2.
=72 ms.
-Oh callum the reason you make you feel weightless is because all your weight is being used for centriptal force. So mrw-^2=mg kinda like when your on top of a ride and you feel weightless.
+ your method for finding the E/16 just saw it.. Its longer if you do it that way.. when I did it i got 51 as time constant.Last edited by FrightBright; 03-06-2012 at 18:19. -
Re: AQA Physics A - PHYA4 (11/06/12) - Exam threadso which answer is right ?(Original post by FrightBright)
Thanks capacitance is constant.
Half life is 36ms.
Energy strored is 1/2(Q)(V^2)
So you want the voltage to drop to 1/4(V) because when you square it it's 1/16.
So just 36x2.
=72 ms.
-Oh callum the reason you make you feel weightless is because all your weight is being used for centriptal force. So mrw-^2=mg kinda like when your on top of a ride and you feel weightless.
+ your method for finding the E/16 just saw it.. Its longer if you do it that way.. when I did it i got 51 as time constant. -
Re: AQA Physics A - PHYA4 (11/06/12) - Exam threadB-72 ms(Original post by callmenighthawk)
so which answer is right ?
51 is time constant which is RC
Thats not the same as t
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Re: AQA Physics A - PHYA4 (11/06/12) - Exam threadIts in phase with velocity which is 90 degrees out of phase with displacement.(Original post by Next Level)
I don't get resonance, as in why the driving freq must equal the natural one, why it's 90 degrees out of phase, all this business of forced and free vibrations etc...any good videos on the topic?
look at graphs pg 36 nelson thornes
Hope that helps. -
Re: AQA Physics A - PHYA4 (11/06/12) - Exam threadright, my teacher told me it's always best to use 1/2CV^2 when doing calculations.
yeah I thought I understood why it was 90 degree out of phase before because I said Force = mass x velocity, when it's mass x acceleration.
I know it's to oppose the natural restoring force but I don't know how to word it.