AQA Physics A - PHYA5 (18/06/12) - Exam thread
Physics exam discussion - share revision tips in preparation for GCSE, A Level and other physics exams and discuss how they went afterwards.
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Re: AQA Physics A - PHYA5 (18/06/12) - Exam threadim not sure about deriving it, but i think we need to know about the assumptions and about collisions and force and time with the walls of the container(Original post by callmenighthawk)
can someone PLEASE help me with the
derivation.
my teacher said we won't need to know how to derive it fully, just understand why it is derived like that (what laws and principles are happening) as it's never come up as fully deriving it. -
Re: AQA Physics A - PHYA5 (18/06/12) - Exam threadhere(Original post by kimmey)
hi does anyone have the mark scheme to the exam style questions right at the end of the book. i have chapters 9-12 but i dont have the ones right at the end. if anyone could post a link to them i would be eternally grateful
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Re: AQA Physics A - PHYA5 (18/06/12) - Exam threadI'm fairly sure that you do need to be able to derive it fully. Although they won't ask you to do so, as it will be too time-consuming, they could potentially ask you to derive any part of it.(Original post by callmenighthawk)
can someone PLEASE help me with the
derivation.
my teacher said we won't need to know how to derive it fully, just understand why it is derived like that (what laws and principles are happening) as it's never come up as fully deriving it.
What don't you understand about the derivation? It's probably better to give you a tailored response rather than regurgitating the textbook.
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Re: AQA Physics A - PHYA5 (18/06/12) - Exam threadI'm poor at derivation, if you could go through all of it (practice for you too(Original post by Onee-chan)
I'm fairly sure that you do need to be able to derive it fully. Although they won't ask you to do so, as it will be too time-consuming, they could potentially ask you to derive any part of it.
What don't you understand about the derivation? It's probably better to give you a tailored response rather than regurgitating the textbook.
) then that would be great.
If not then I'll get back to you soon on what parts I don't understand
thanks man -
Re: AQA Physics A - PHYA5 (18/06/12) - Exam thread
Do we need to know an experiment in detail to work out radius of the nucleus?
Also, is this derivation good enough for kinetic theory? :
- consider box of molecules
- change in momentum=2mv
- time between collisions=(2l)/v
- F=(mv^2)/l
- P=(mv^2)/V
- considering N molecules: P=(Nm(average speed)^2)/V
- Considering three dimensions: P=(1/3)(Nm(average speed)^2)/V
Leading to
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Re: AQA Physics A - PHYA5 (18/06/12) - Exam thread931.3 - I have never come across 931.5 in any mark schemes and its says 931.3 in the formulae booklet(Original post by Glacier)
Are we supposed to use 1 u = 931.3 MeV or 931.5 MeV? The textbook says 931.3, but the furmulae booklet says 931.5 MeV.
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Re: AQA Physics A - PHYA5 (18/06/12) - Exam thread
Are the astrophysics papers found here (June 2006, 2007 and 2008) relevant to the astrophysics exam this year on the 18th? thanks
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Re: AQA Physics A - PHYA5 (18/06/12) - Exam threadAccording to http://store.aqa.org.uk/qual/gce/pdf...5-W-A2-DFB.PDF, "1u is equivalent to 931.5 MeV", under "atomic mass unit" on the first page.(Original post by lee_vassallo)
931.3 - I have never come across 931.5 in any mark schemes and its says 931.3 in the formulae booklet -
Gotta be unit 5(Original post by internet tough guy)
unit 4 or unit 5, which is more difficult do you all think?
This was posted from The Student Room's iPhone/iPad App -
Re: AQA Physics A - PHYA5 (18/06/12) - Exam thread(Original post by callmenighthawk)
I'm poor at derivation, if you could go through all of it (practice for you too
) then that would be great.
If not then I'll get back to you soon on what parts I don't understand
thanks man
To Callme: Looks like there's your prove(Original post by number23)
Do we need to know an experiment in detail to work out radius of the nucleus?
Also, is this derivation good enough for kinetic theory? :
- consider box of molecules
- change in momentum=2mv
- time between collisions=(2l)/v
- F=(mv^2)/l
- P=(mv^2)/V
- considering N molecules: P=(Nm(average speed)^2)/V
- Considering three dimensions: P=(1/3)(Nm(average speed)^2)/V
Leading to
.
To number: I think we need to know the 3 experiments: alpha scattering then use probability to estimate the ratio of nuclear to atomic diameter, calculating the least distance of separation and high energy electron diffraction. -
Re: AQA Physics A - PHYA5 (18/06/12) - Exam threadI can do it now, thank you anyway(Original post by Onee-chan)
To Callme: Looks like there's your prove
.
To number: I think we need to know the 3 experiments: alpha scattering then use probability to estimate the ratio of nuclear to atomic diameter, calculating the least distance of separation and high energy electron diffraction.
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Re: AQA Physics A - PHYA5 (18/06/12) - Exam threadhow(Original post by Onee-chan)
To Callme: Looks like there's your prove
.
To number: I think we need to know the 3 experiments: alpha scattering then use probability to estimate the ratio of nuclear to atomic diameter, calculating the least distance of separation and high energy electron diffraction. -
Re: AQA Physics A - PHYA5 (18/06/12) - Exam threadwell as the alpha particle approaches the atom kinetic energy gets converted to electric potential energy.(Original post by callmenighthawk)
how
so i think...
0.5mv^2=Qq/4piepsilon0R
where R is the least distance of separation