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# November 2003 S1 Question

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1. How would you do part a)? The mark scheme has me stumped :/
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2. Nov 2003 question.docx (235.9 KB, 233 views)
3. (Original post by Dirtyflanker)
How would you do part a)? The mark scheme has me stumped :/
Its a discrete uniform distribution, so use the formula,
4. (Original post by raheem94)
Its a discrete uniform distribution, so use the formula,
I did that but to get all the marks you have to derive it from the probability distribution
5. (Original post by Dirtyflanker)
I did that but to get all the marks you have to derive it from the probability distribution

Use for

Now input the values and find
6. Wow, thanks wouldn't have expected the need for that formula in an s1 exam though :s
7. help me please..... who knows how to do the probabiltity question q2..
q: a fairground game involves trying to hit a moving target with a gunshot. a round consists of up to 3 shots. ten points are scored if a player hits the target, but the round is over if the player misses. linda has a constant probability of 0.6 of hitting the target and shots are INDEPENDENT OF ONE ANOTHER. (WHAT DOES THIS MEAN, HOW CAN I SHOW IT ON A TREE DIAGRAM OR ISIT A VENN DIAGRAM??)

a) find the probability that linda scores 30 points in a round

The r.v X is the no. of points linda scores in a round.
b) find the probability distribution of X
c) find the mean n SD of X

A game consists of 2 rounds
d)find the probability that linda scores more points in round 2 than in round 1.
8. Don't have the answers in front of me, but I sort of remember doing it a while back:
a) P(HHH) = 0.6 x 0.6 x 0.6
b) x 0 10 20 30
P(x)0.4 0.6x0.4 0.6x0.6x0.4 0.6x0.6x0.6

See the tree diagram attached. By independent- it just means that the probability of the next event happening is not dependent on the previous probability ie- a hit is always 0.6 and a miss is always 0.4.

c) Just use the formulas
d) Always write out what the possibilities are, so if she needs more points in round 2 than in round 1 you can write it out as:

Round 2 Round 1
P(10) P(0) Multiply each set together and add up all the probabilities and that's your answer
P(20) P(0)
P(30) P(0)
P(20) P(10)
P(30) P(10)
P(30) P(20)

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