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AQA MPC2 (Core 2) Exam June 2012

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Hiya, I believe this is what I did...

Made them equal to each other so.. (all logs here to base 10!)
1+2logx = log(x^2+1)
log10 + logx^2 = log(x^2+1)
log10x^2=log(x^2+1)
therefore 10x^2=x^2+1
which rearranges to get x= +1/3 and -1/3

you are told P is positive so its x coordinate must be +1/3
i subbed this into a starting equation to get y=log(10/9)

I then used gradient = rise/run

so gradient = (log(10/9))/(1/3)
=3log(10/9)
=log(10/9)^3
=log(1000/729)

hope this helps! :smile:

Quite annoying how easy that was ¬.¬, oh well only dropped 3 marks I think. What will it be for 100 UMS you reckon?

Reply 181

Jit-Mistry

Original post by nathano14

So the exam is over, what did everyone think about it?

Mpc2 was pretty good, besides question 8 and 9 which took the piss since our teacher didnt teach up transformations and logs thoroughly... Q 8 & 9 was worth 23 marks alone by the way... i personally believe and A will be around 59-61 for an A...

If anyone can post an unofficial markscheme for mpc1.. DO IT!

Reply 182

x_Raman_96

What did you guys get for the trig identities question I got: 60 and 135 :s-smilie:

Reply 183

madiha28

Original post by raheem94

(tan \theta + 1)(sin^2 \theta - 3 cos^2\theta) = 0

You will get two equations,

tan \theta = -1 \ \ and \ \ sin^2 \theta -3 cos^2 \theta =0

The second equation can be simplified,

sin^2 \theta -3 cos^2 \theta =0 \implies sin^2 \theta = 3 cos^2 \theta \implies tan^2 \theta = 3 \implies tan \theta = \pm \sqrt3

when you divide Sin2x by sin2x doesn't it become 1 ? So therefore answer is 1/3

Reply 184

ryanboi

Original post by x_Raman_96

What did you guys get for the trig identities question I got: 60 and 135 :s-smilie:

60, 120 and 135

Reply 185

x_Raman_96

Original post by ryanboi

60, 120 and 135

****! Will I only lose 1 mark for missing 120? or 2?

Reply 186

raheem94

Original post by madiha28

when you divide Sin2x by sin2x doesn't it become 1 ? So therefore answer is 1/3

I am dividing both sides by

cos^2 \theta

Reply 187

ryanboi

Original post by x_Raman_96

****! Will I only lose 1 mark for missing 120? or 2?

question is out of 3 marks so i guess 1 mark for each solution so yeah lose 1 mark i guess

Reply 188

ummm

I thought that paper was a lot harder than the past papers, so hopefully low grade boundaries.
I think I managed to get an answer for everything except that 'describe the stretch' log type question, which I screwed up. :frown:

fml.

C1 was alright though!

(edited 11 years ago)

Reply 189

ashton.gibbs

Original post by mark17188

Quite annoying how easy that was ¬.¬, oh well only dropped 3 marks I think. What will it be for 100 UMS you reckon?

I seriously don't have a clue! I don't really understand how UMS works haha :tongue:

Reply 190

Rainingshame

Original post by ashton.gibbs

I seriously don't have a clue! I don't really understand how UMS works haha :tongue:

last year 54 was an A but 75 was 100 as a reference.

Reply 191

Nick9001

Everything before question seven was fine. When it got to there, I died a little inside.

Reply 192

rawwwr24

I thought most of the paper was easy just a few questions near the end were hard but to be honest core 1 was harder in my opinion

Reply 193

b_ellis

Did people get 222m^2 for the area of the shaded region? or there abouts?

Reply 194

iceman95

Original post by rawwwr24

I thought most of the paper was easy just a few questions near the end were hard but to be honest core 1 was harder in my opinion

Yes last two questions in logs wer really harder than the past paper logs. C1 was pretty easy.

Reply 195

JoeUtd

What did people get for Tan solutions? It was 4 marks and I thought all you had to do wan tan x = -1 so tan^-1 = -45 and then give solutions. But it seemed too easy for the marks, so it's probably wrong