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# OCR Physics A G481 Mechanics [Thursday 17th May 2012]

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1. (Original post by JohnSimmons)
Did you work use SUVAT to work out displacement? Then put that into work done is force x distance? Then divide by time?

That's what I did but I cant remember my answer :\

Also, what was the answer to the previous question. The one where you had to work out the force of the spring or something?
i did that...but i thought you divide the time by 2 coz ur working out half the distance??? i dunno....i was not very confident with it....
2. When both rockets A an B are on, the forces are equal so there is a torque which produces a turning force/rotational force- so it rotates?
When just A is turned on, the net force favours the direction of A since A>B. I think?

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3. (Original post by stackemup)
Yes so happy, took me quite a bit of working, but I got 2.6 as well.

Damn, that 5 mark deforming solids qualitative question took the absolute p***.
4. (Original post by blackhole)
It was a glider and a spring. You had previously worked out the force. You are then given a time of 0.094 seconds (I think) and are told to work out the rate of work done.
5. (Original post by blackhole)
Well there was a spring with force constant 50 and was compressed by 0.07 metres. The time the force was applied for - or something like that - was 0.094 seconds.
Really interested as to how everyone got 2.6 as i could not do this question for the life of me!
6. I messed up this exam.
7. Wasn't the energy stored in the spring 1/2kx^2
So the energy stored was 0.5 x 50 x 0.07^2 = 0.1225 j
So energy done per second is 0.1225 / 0.094 = 1.30

I left my answer as 1.30 so I must of missed something... but oh well.
8. sooo not looking forward EWP...
9. I got 2.6 but just realised its 1.3

I did work done/time

So I did the force x distance / time

However work done for a spring is area under a graph

So its half the force times distance / time which is 1.3

Bugger
10. (Original post by JuxtaposedJames)
I got 2.6 but just realised its 1.3

I did work done/time

So I did the force x distance / time

However work done for a spring is area under a graph

So its half the force times distance / time which is 1.3

Bugger
crap! i did the same thing...
11. (Original post by striver17)
crap! i did the same thing...
I think everyone did as everyone thinks 2.6 is the right answer...
12. can someone please make an unofficial markscheme???
13. (Original post by Butterkist123)
I thought the angle was 31 not 59. Because it went 30 up and 18 across..not the other way round.
Yeah, I agree with you. I got 31 too...
14. (Original post by sarah-xx)
Yeah, I agree with you. I got 31 too...
Me too
15. 31 is wrong.. :'( apparently it said between horizontal
16. (Original post by emah123)
can someone please make an unofficial markscheme???
If somebody has the paper I will make an unofficial mark scheme, I can remember most of the questions and answers but I really don't want to do a MS without the paper tbh, I got around 53-54/60 Which should hopefully be 90+ UMS I would suspect based upon previous boundaries.
17. Who gets access to the paper after we've done it? Is it only teachers?
18. What do people reckon full ums boundary and A boundary will be

Force for glider question was 3.5N
work done or whatever it was for that question i got 1.30 cause work done is 1/2fx not fx
mass 119kg
for the further reason why it is better for last question i said about energy supply is constant
2 angle questions i got 11 something and 53 i think
efficiency 27.3% rounded

WHAT WAS THE ROCKETS ABOUT NET FORCE OR NET MOMENT? cause how can you assume that it creates a turning effect
19. and what did people for the initial KE question, i said that energy was not totally transferred from KE to GPE
and what did people for the initial KE question, i said that energy was not totally transferred from KE to GPE
Only the vertical component of kinetic energy will be converted.

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