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# Mr M's OCR (not OCR MEI) Core 1 answers May 2012 Tweet

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1. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by AspiringDoctor)
Have to say a massive thank you to Mr M for your time and effort I don't think I did very well but at least the answers can let my mind rest and not fret about what the answers could have been.
You are welcome
2. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by Kabelan1)
Hi Mr M,

Approximately how much from the other two AS units e.g C2 and D1,
would be required if I got an average B in this June 2012 C1 paper.
Required for what?
3. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by BillyFord188)
For some odd reason on 10iv) I formed the quadratic by subbing in y=2x; but instead of then finding the discriminant as normal I just factorised using the formula and got two horrible surd answers, would I still get the 3/5 marks for forming the correct quadratic?
Probably, might be 2/5
4. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by pzoDe)
Ah Mr M, if you're looking at this, I see what he means. I have repeated 9(ii) twice. The first 9(ii) needs to become 9(i).
Ok changed
5. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by Mr M)
100 UMS is calculated from a mathematical formula that depends on the position of the other grades. Just wait and see.
Sorry for bothering you again but I just realised what I did wrong for 9(i) after trying to work through it again. Can't believe I didn't spot it while checking, I had half an hour :/
So.. I did something along the lines of:
4x(x+3) <112
4x^2 + 12 < 112 Missed out the x by accident here ugh.
X^2 < 25
I drew a graph of y = x^2 - 25 and got the intercepts as 5, -5
then stated that -5 < x < 5

Any idea how many marks I would get? Just one for forming the inequality they asked for?
Last edited by Millyshyn; 17-05-2012 at 07:57.
6. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
I can't remember what I got for all my questions but a lot of those figures seem familiar, heres hoping I got an A this time around xD thanks Mr M!
7. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by pzoDe)
It depends on what you want to get.
Your final OCR Maths grade is determined by your average percentages in AS and A2 (as far as I am aware; this may only be strictly for A*).
A*: You need an average of 80% in your AS modules and an average of 90% in your A2 modules.
A: You need an average of 80% in both AS and A2 modules
B: You need an average of 70% in both AS and A2 modules
Hi, I don't think this is quite right. I was told that to get the A*, you need an average of 80% over BOTH AS and A2 (which could work out as 70% and 90%, 60% and 100%), as long as you have 90% or above in your A2 modules. Obviously, it is quite unlikely that someone getting a low B will actually proceed to get 90% in their A2, unless there was some particular reason for their B, but it is possible.
8. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by Millyshyn)
Sorry for bothering you again but I just realised what I did wrong for 9(i) after trying to work through it again. Can't believe I didn't spot it while checking, I had half an hour :/
So.. I did something along the lines of:
4x(x+3) <112
4x^2 + 12 < 112 Missed out the x by accident here ugh.
X^2 < 25
I drew a graph of y = x^2 - 25 and got the intercepts as 5, -5
then stated that -5 < x < 5

Any idea how many marks I would get? Just one for forming the inequality they asked for?
You might get 3 marks if you are lucky.
9. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by Holz888)
Hi, I don't think this is quite right. I was told that to get the A*, you need an average of 80% over BOTH AS and A2 (which could work out as 70% and 90%, 60% and 100%), as long as you have 90% or above in your A2 modules. Obviously, it is quite unlikely that someone getting a low B will actually proceed to get 90% in their A2, unless there was some particular reason for their B, but it is possible.
You are probably correct, I wasn't 100% - I mean 90% - sure about what I said.

Just to clarify the 90% average is required in C3 and C4 (for example 80% and 100%).
10. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
Hi Mr M,

Earlier you confirmed that I would get some marks for an answer of Y=2x - 5 - for one of the questions as I got the gradient right. The question was out of 4 marks - Are you able to say how many marks you think I might get ?

Thanks...
11. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by mcquitmp)
Hi Mr M,

Earlier you confirmed that I would get some marks for an answer of Y=2x - 5 - for one of the questions as I got the gradient right. The question was out of 4 marks - Are you able to say how many marks you think I might get ?

Thanks...
2 I expect
12. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by Mr M)
100 UMS is calculated from a mathematical formula that depends on the position of the other grades. Just wait and see.
The grade boundaries are only decided for A and E, right?

100UMS means A+2(A-B), can you please confirm it.
13. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by raheem94)
The grade boundaries are only decided for A and E, right?

100UMS means A+2(A-B), can you please confirm it.
I think so but it doesn't always look like that, there might be a difference of 1 raw mark between each boundary sometimes (due to the real boundaries being decimals and then rounded).

e.g. 30 for an E, 37.4 for a D (rounded to 37), and then 44.8 (rounded to 45) . So the differences in grades look different.
14. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by raheem94)
The grade boundaries are only decided for A and E, right?

100UMS means A+2(A-B), can you please confirm it.
A, C and E I think.

The other formula is right from memory but I don't have the time now to look it up.
15. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
Working with allocated marks:

1.
[1]
[1]
[1]
2.
(Original post by (i))
[1]
(Original post by (ii))
[1]
[1]
(Original post by (iii))
x [1]
[1]
3.
(Original post by (i))

[1]
(Original post by (ii))

[1]

[1]
PQ [1]
PQ
PQ [1]

Not sure about the 3rd mark I allocated here
4.
(Original post by (i))
[1]
[1]
[1]
[1]
(Original post by (ii))
[2]

or

[2]

Note: If you got (i) wrong, then you will should get ecf for either [1] or [2] marks
5.
(Original post by (i))

Marks for following:
Curve has a descreasing gradient and only in quadrant positive for and [1]
Curve goes through (0,0)[1]
(Original post by (ii))
\boxed{Curve is translated 4 units in the positive -direction} (owtte)

Marks for following:
Translated 4 units [1]
Positive -direction [1]

Note: you may get [1] mark for 'in the right direction'
(Original post by (iii))
or the same in a different format [2]

or

[1]

Not sure whether the incorrect equation gains a mark or not.
6.

[1]
tangent [1]
tangent
normal [1]
[1]
[1]
(or alternative method of finding the equation of the line) [1]

[1]

Not sure about some of the allocated marks. I gave method over answer where necessary.
7.
Stating (or other variable instead of , e.g , )

Complete the square:

[1]

[1]

[1]

[1]
[1]

[1]
[2] ([1] if only +6 or only -6 coefficient of / one of the values of 16 or 6 is incorrect)

(can be done without substitution of (or a different variable) for )

Not completely sure about allocated marks
Last edited by pzoDe; 17-05-2012 at 18:37.
16. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by pzoDe)
Working with allocated marks:

1.

2.

3.

4.

5.

6.

7.

Will finish tomorrow evening after C2.
For 5ii) Would you get the two marks if you put "translated to units to the right" and also in 5iii) I put 5 to the power of -1 , is that right? Thanks.
17. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by olivers16)
For 5ii) Would you get the two marks if you put "translated to units to the right" and also in 5iii) I put 5 to the power of -1 , is that right? Thanks.
If you mean "translated two units to the right" you will only get one of the marks (if they allow 'to the right' instead of positive -direction) as it was translated four units, not two.

As for , if you did any of these you will get the marks:

Last edited by pzoDe; 17-05-2012 at 14:31.
18. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by pzoDe)
If you mean "translated two units to the right" you will only get one of the marks (if they allow 'to the right' instead of positive -direction) as it was translated four units, not two.

As for , if you did any of these you will get the marks:

Thank you. How do you know this? Have u seen the mark scheme?
19. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
Here are the solutions to the paper:

Q1:

Q2:
(i)
(ii)

Q3:
(i)

(ii)
When crosses the axis, .

When crosses the axis, .

Midpoint of is

Q4:
(i)

(ii)
The vertex of the parabola is its max/min point.
The minimum of this curve is at
Sub in in

Coordinates of the vertex

Q5:

(i)

(ii)

Horizontal shift of 4 units in the direction.

(iii)

Q6:

Differentiate it.

Sub in

Find the y-coordinate at ,

Use

Q7:

Q8:

(i)

Differentiate with respect to

At stationary point gradient equals zero.

Sub in in
Coordinates of stationary point are:

(ii)
Find the second derivative.

Sub in ,

(iii)
Find

Q9:

Area = length x width =

Solve

Draw the graph of

The region of is
Length is always positive, hence, the range is

(ii)

Q10:

(i)

(ii)

Find the gradient of the line

Use

(iii)
Use

hence lies inside circle.

(iv)

Sub in in

The equation has no roots, hence it doesn't meets the circle.

I haven't revised my post, if there is any mistake please tell me.
20. Re: Mr M's OCR (not OCR MEI) Core 1 answers May 2012
(Original post by pzoDe)
...
Oh i didn't saw that you are also doing the solutions!
I was in the process of typing my post that time, hence didn't noticed it.
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