[Abblecrumble]

Hello!
Please can someone clear this up for me?

The ball is moving horizontally at 6.0ms^-1 when it hits the wall. The ball is in contact with the wall for 0.16s and rebounds horizontally at 4.0ms^-1. Calculate, for the time that the ball is in contact with the wall, the change in velocity of the ball.

I thought to work our the change in velocity you calculate V₁-V₂, so 6-4=2, but in the mark scheme it says the change in velocity is 10ms^-1.
Please can someone explain this?
♥

[Stonebridge]

(Original post by Abblecrumble)
Hello!
Please can someone clear this up for me?



I thought to work our the change in velocity you calculate V₁-V₂, so 6-4=2, but in the mark scheme it says the change in velocity is 10ms^-1.
Please can someone explain this?
♥

The ball changes direction.
Velocity is a vector.
If the velocity is initially 6m/s then after the collision it is -4m/s

[Abblecrumble]

(Original post by Stonebridge)
The ball changes direction.
Velocity is a vector.
If the velocity is initially 6m/s then after the collision it is -4m/s

Oh, so it's 6-(-4)? So, that's 10. Haha, that was easy enough.
Thank you!