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# Change in Velocity Tweet

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1. Change in Velocity
Hello!
Please can someone clear this up for me?

The ball is moving horizontally at 6.0ms-1 when it hits the wall. The ball is in contact with the wall for 0.16s and rebounds horizontally at 4.0ms-1. Calculate, for the time that the ball is in contact with the wall, the change in velocity of the ball.
I thought to work our the change in velocity you calculate V1-V2, so 6-4=2, but in the mark scheme it says the change in velocity is 10ms-1.
Please can someone explain this?
2. Re: Change in Velocity
(Original post by Abblecrumble)
Hello!
Please can someone clear this up for me?

I thought to work our the change in velocity you calculate V1-V2, so 6-4=2, but in the mark scheme it says the change in velocity is 10ms-1.
Please can someone explain this?
The ball changes direction.
Velocity is a vector.
If the velocity is initially 6m/s then after the collision it is -4m/s
3. Re: Change in Velocity
(Original post by Stonebridge)
The ball changes direction.
Velocity is a vector.
If the velocity is initially 6m/s then after the collision it is -4m/s
Oh, so it's 6-(-4)? So, that's 10. Haha, that was easy enough.
Thank you!
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