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OCR MEI C2 MAY 18th

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Reply 60
Good luck everyone, lets hope you don't get a stinker of an exam like I did this time last year.
Reply 61
Original post by GreenLantern1
Of course they do! You are plottting the same thing!


Um, actually while y = -sin(x) and y = sin(-x) are equivalent, y = -cos(x) is not the same as y = cos(-x), in fact they are actually reflections of one another.

for example, take x = 0, y = -cos(x) = -cos(0) = -1
... but, y = cos(-x) = cos(0) = 1, not -1
Reply 62
Original post by skibur
Good luck everyone, lets hope you don't get a stinker of an exam like I did this time last year.


I hope we don't get a super hard one!
Thanks for the luck! Good luck with your A2s :smile:
Reply 63
Feeling a little bored, so does anyone have any quick maths questions on C2 they want answering :wink:
Reply 64
Original post by darbyj
Feeling a little bored, so does anyone have any quick maths questions on C2 they want answering :wink:


Could you explain what first principles are?
I don't have a clue and maybe you could help :smile:
Reply 65
Original post by Alotties
Could you explain what first principles are?
I don't have a clue and maybe you could help :smile:


Sure, I'd like to help if I can :smile:

First principles is a proof used to show the principle of differentiation. In essence it is similar to the the idea that gradient is change in y over change in x.

For example; a first principle would be f(x+h) - f(x) all divided by x

Why?

Well, if you are taking a starting value of x as being x (in this example) and then moving a very small distance, h then your change in x will be h.

Equally, your change in y, will be the difference between f(x) and f(x+h).

The idea being that h will tend to zero, thus leaving you with the same result, as though you have differentiated normally.
Reply 66
So who has yet to start revision?
Reply 67
Original post by darbyj
Sure, I'd like to help if I can :smile:

First principles is a proof used to show the principle of differentiation. In essence it is similar to the the idea that gradient is change in y over change in x.

For example; a first principle would be f(x+h) - f(x) all divided by x

Why?

Well, if you are taking a starting value of x as being x (in this example) and then moving a very small distance, h then your change in x will be h.

Equally, your change in y, will be the difference between f(x) and f(x+h).

The idea being that h will tend to zero, thus leaving you with the same result, as though you have differentiated normally.


Ohhh! I think I see.
I have done some of these questions I think but never knew they were first principles :tongue:
Thank you (+1 for your help) :smile:
Reply 68
That may not be very clear, so I am using the past paper from June 2009 to illustrate my point;

12 i) Calculate the gradient of the chord joining the points on the curve y = x2 - 7 for which x = 3 and x = 3.1

gradient = ( f(3.1) - f(3) ) / (3.1 - 3) = 0.61/0.1 = 6.1

ii) Given that f(x) = x2 - 7, find and simplify ( f(3+h) - f(3) ) / h

So substituting into the equation of the curve;

f(3 + h) = (3 + h)2 - 7 and f(3) = 2

so ( f(3+h) - f(3) ) / h = (9 + 6h + h2 - 7 - 2) / h = ( 6h + h2 ) / h = 6 + h

Notice anything about this? If you were to differentiate y = x2 - 7, and use that to find the gradient at x = 3, you would get the result 6. Well here you have got the result 6 + h, and if you take h as being very small (i.e. zero) then it is just 6.

I hope that helped!
(edited 11 years ago)
Reply 69
Original post by Alotties
Ohhh! I think I see.
I have done some of these questions I think but never knew they were first principles :tongue:
Thank you (+1 for your help) :smile:


Glad I could help :biggrin:
Reply 70
Original post by darbyj
Glad I could help :biggrin:


I understand it a lot better now hehe :biggrin:
If it comes up tomorrow I hope I remember what you've said xD
Reply 71
I always forget, can someone remind me about this:

If log10 A = c, why does A = 10^c?
Original post by ILM16
I always forget, can someone remind me about this:

If log10 A = c, why does A = 10^c?


it just does ok
Reply 73
Original post by ILM16
I always forget, can someone remind me about this:

If log10 A = c, why does A = 10^c?


Its just a rule of logs... I know its stupid :frown:
Reply 74
Do we need to know y=-sin(X) and y=sin(-x) im pretty sure we don't... Isnt that a reflection of the graph and is c3?
I always forget, can someone remind me about this:

If log10 A = c, why does A = 10^c?


log10 A has the base of 10 and has the interger of A
to solve for A you have to get rid of the log to do this you have to raise the "other" side to the power of the base hense A = 10^c
hope this helped
im gona get parred so badly im **** at this c2
Judging by the rate at which im going through a past C2 exam paper right now 12 hours before the exam, Im going to FLOP this exam


don't worry you'll be fine just do lots of past papers if you stuck on a question then just ask i will try my best to answer it :biggrin:
does anyone know the proper way to write about the limit h-->0 ?

Is it as h tends to 0, dy/dx tends to the gradient of the tangent to the curve??

I am really stuck on this.
Reply 79
Original post by thegreenchildren
does anyone know the proper way to write about the limit h-->0 ?

Is it as h tends to 0, dy/dx tends to the gradient of the tangent to the curve??

I am really stuck on this.


...at a certain point.

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