[erniiee]

(Original post by hannah1994)
do we have to know ln abbreviation thing for logs in C2?

It could come up I suppose as its in my textbook, just remember its log base e (natural log). Same as log base 10 being lg.

(Original post by Genesis2703)
In Jan 2011 the last question was factor/remainder theorum (with intergrating curves) so it could indeed come up

Oooo I always think for some reason, the paper 3 sessions back will be most similar so lets hope and pray! Just did the Jan 10 paper and gonna mark it..wish me luck

[Genesis2703]

(Original post by Konshi)
No, I did the 2nd solution on the mark scheme. How does the 1st one work with tan?

I havent seen the mark scheme, but what I have done was divide both sides by Cos 2x. making 1 = 3^0.5 sin2x/cos2x

sin2x/cos2x = tan2x due to trig identities we know, and then you rearrange and solve.

EDIT: ln logs with e etc. arent meant to come up in C2, they arent in any of our school books and the teacher said that it was C3 knowledge. It will not come up at all I assure you (if it does... I will be held liable)

And ernie, with most subjects I think everything is meant to have been examined in a 4 paper cycle/basis (this is what AQA ICT is like anyway) so you might be right haha :P

[Konshi]

(Original post by peachesandcream77)
im doing the jan 12 c2 paper. can someone please explain on question 7B, why the limits are between 1 and 0 and between 2 and 0.. I don't understand..

Just did this Q again. You need to split the area into 2 separate areas down the middle from the point of intersection. We know that along this split, x=1 from the coordinates (1,6). This gives the limits for the first area as 1 and 0.

We then need to find the point where the second line intercepts the x axis. I input x = 2 into both lines, and for the line 8x^-2 -2 when x=2, y=0. Therefore we know the point is 2, and the limits for the second area are 2 and 1.

Then you just work it out as usual. Hope this helped.

[peachesandcream77]

(Original post by Konshi)
Just did this Q again. You need to split the area into 2 separate areas down the middle from the point of intersection. We know that along this split, x=1 from the coordinates (1,6). This gives the limits for the first area as 1 and 0.

We then need to find the point where the second line intercepts the x axis. I input x = 2 into both lines, and for the line 8x^-2 -2 when x=2, y=0. Therefore we know the point is 2, and the limits for the second area are 2 and 1.

Then you just work it out as usual. Hope this helped.

oh ok, I see thanks. I don't think i've come across a question where i've had to split it.. when do i usually have to do this? usually i know i have to split it if a certain area is under the x axis then the answer is negative but why do i need to split it now?
is it something to do with the shape of the curve?

[Konshi]

(Original post by Genesis2703)
I havent seen the mark scheme, but what I have done was divide both sides by Cos 2x. making 1 = 3^0.5 sin2x/cos2x

sin2x/cos2x = tan2x due to trig identities we know, and then you rearrange and solve.

EDIT: ln logs with e etc. arent meant to come up in C2, they arent in any of our school books and the teacher said that it was C3 knowledge. It will not come up at all I assure you (if it does... I will be held liable)

And ernie, with most subjects I think everything is meant to have been examined in a 4 paper cycle/basis (this is what AQA ICT is like anyway) so you might be right haha :P

Agh, tbh I'm more comfortable with using the sin2x + cos2x = 1 identity, so I'll stick with that I guess :P

How do you convert from degrees into exact radians? I know to divide by 180 and x by Pi, like for 15 degrees that'll give 0.262, but I want it as Pi/12.

(Original post by peachesandcream77)
oh ok, I see thanks. I don't think i've come across a question where i've had to split it.. when do i usually have to do this? usually i know i have to split it if a certain area is under the x axis then the answer is negative but why do i need to split it now?
is it something to do with the shape of the curve?

When the area under the curve isn't definitive. It's usually when curves overlap each other that you need to split it into different areas.

[Genesis2703]

(Original post by peachesandcream77)
oh ok, I see thanks. I don't think i've come across a question where i've had to split it.. when do i usually have to do this? usually i know i have to split it if a certain area is under the x axis then the answer is negative but why do i need to split it now?
is it something to do with the shape of the curve?

It is because in said case, the 2 curves are occupying different areas in terms of x-axis, on the diagram, as from the intersection point, 1 curve is making the areas right of it, and the other curve is making the area left of it

EDIT: Konshi, have you tried turning your calculator into radians mode, I think then it will do what you want.

[erniiee]

(Original post by Genesis2703)
I havent seen the mark scheme, but what I have done was divide both sides by Cos 2x. making 1 = 3^0.5 sin2x/cos2x

sin2x/cos2x = tan2x due to trig identities we know, and then you rearrange and solve.

EDIT: ln logs with e etc. arent meant to come up in C2, they arent in any of our school books and the teacher said that it was C3 knowledge. It will not come up at all I assure you (if it does... I will be held liable)

And ernie, with most subjects I think everything is meant to have been examined in a 4 paper cycle/basis (this is what AQA ICT is like anyway) so you might be right haha :P

I really do hope so..gonna do the June 10 and Jan 11 papers today and look through all of the last questions from the specimen paper.

[erniiee]

(Original post by Konshi)
Agh, tbh I'm more comfortable with using the sin2x + cos2x = 1 identity, so I'll stick with that I guess :P

How do you convert from degrees into exact radians? I know to divide by 180 and x by Pi, like for 15 degrees that'll give 0.262, but I want it as Pi/12.

Divide by 180. multiply the numerator by pi. e.g.
140/180=7/9
7/9*pi=7pi/9

[Genesis2703]

^Good idea Ernie @what papers to do, Im planning to do May 2010, June 2011 and Jan 2012 today (eating dinner now)

[peachesandcream77]

(Original post by peachesandcream77)
oh ok, I see thanks. I don't think i've come across a question where i've had to split it.. when do i usually have to do this? usually i know i have to split it if a certain area is under the x axis then the answer is negative but why do i need to split it now?
is it something to do with the shape of the curve?

hey sorry but i still dont quite understand how to get 2. did you just use guesswork, assumed it is likely it was 2 then plug it in?
assuming in other case where you can't do that, i've tried substituting when y = 0 to find out the value of x but its coming up with some weird decimal numbers..

[erniiee]

(Original post by Genesis2703)
^Good idea Ernie @what papers to do, Im planning to do May 2010, June 2011 and Jan 2012 today (eating dinner now)

Dinner?! Or lunch?

Ah okay, I'll tell you how I do and I might even ask you any questions on things I don't understand

good luck for your papers.

How did you do in C1?

[mora11]

(Original post by hannah1994)
do we have to know ln abbreviation thing for logs in C2?

no

[Konshi]

(Original post by erniiee)
Divide by 180. multiply the numerator by pi. e.g.
140/180=7/9
7/9*pi=7pi/9

Been playing around with my calculator, I had it in LineIO mode, when turning it into MathIO mode it displays answers as fractions. I guess this is what I want yeah?

[peachesandcream77]

(Original post by Genesis2703)
^Good idea Ernie @what papers to do, Im planning to do May 2010, June 2011 and Jan 2012 today (eating dinner now)

hey sorry but i still dont quite understand how to get 2. did you just use guesswork, assumed it is likely it was 2 then plug it in?
assuming in other case where you can't do that, i've tried substituting when y = 0 to find out the value of x but its coming up with some weird decimal numbers..

[erniiee]

(Original post by Konshi)
Been playing around with my calculator, I had it in LineIO mode, when turning it into MathIO mode it displays answers as fractions. I guess this is what I want yeah?

I have no clue as I have a crappy old sharp, which unfortunately doesn't display fractions I think the casios do though, so if that's what you're talking about, then yes

[peachesandcream77]

I'm doing the JAN 12 OCR C2 and I am stuck on a couple of questions, if anyone could help me out it would be greatly appreciated..

Q4, I find bearings really difficult, it's not in my textbook and i've googled to no avail as really complicated stuff keeps coming up. Could someone please really briefly explain bearings?! I have no idea what they are..

Also, I've seen questions saying: find the shortest distance... what does this actually mean?? Something to do with the perpendicular distance is always the shortest.. but how do you find that out?

[Konshi]

(Original post by erniiee)
I have no clue as I have a crappy old sharp, which unfortunately doesn't display fractions I think the casios do though, so if that's what you're talking about, then yes

Yeah been playing around with it a bit more and it seems to do the trick

I also see that you're a fellow 2013 hopeful! (Although I'll be a reapplicant )

[Genesis2703]

(Original post by erniiee)
Dinner?! Or lunch?

Ah okay, I'll tell you how I do and I might even ask you any questions on things I don't understand

good luck for your papers.

How did you do in C1?

i got 89 in c1... which I was unhappy with, BUT i only need 90+ on A2 units for an A* so I dont mind , I got 97 on Fp1 in january as well. I revised FP1 loads and neglected C1 which cost me :/

And yeah Lunch, but I say dinner :P

[Konshi]

Edit: Nvm just figured it out, should've really got that in the actual exam lol

[megank]

Hey guys.. for geometric progression, can the ratio be a negative value?