[bronn]

Argh cannot get my head around histograms

Anyway, this is the question:



I know it must be the simplest thing ever since it's question 3 and worth 3 marks :L

[ztibor]

(Original post by bronn)
Argh cannot get my head around histograms

Anyway, this is the question:



I know it must be the simplest thing ever since it's question 3 and worth 3 marks :L

There is 6 integere values for x in the range of 10-15 which means 2cm for the width of the bar representing this range, and there is 3 integer values in the range of 16-18, which is half of the 6 values.
What do you think about the with of the bar representing this range?
Similarly to the frequencies.
5 cm height represents 15, then 5/15=1/3 cm represents frequency 1.
How many cm represents frequency 9 (9 times 1)?

[bronn]

(Original post by ztibor)
There is 6 integere values for x in the range of 10-15 which means 2cm for the width of the bar representing this range, and there is 3 integer values in the range of 16-18, which is half of the 6 values.
What do you think about the with of the bar representing this range?

Ahh right so the width must be half the width of the range 10-15 so is 1cm?

(Original post by ztibor)
Similarly to the frequencies.
5 cm height represents 15, then 5/15=1/3 cm represents frequency 1.
How many cm represents frequency 9 (9 times 1)?

this doesn't make sense to me? The mark scheme answer is 6cm?