[Blue7195]

(Original post by rawragee)
I have the paper for the Revised Higher exam, I'll pop it up in a bit It looks like our exams were massively different though!

I think it went alright today, I wasn't happy with a few multiple choice questions as they were too complex for only one mark, and I worked out that there was about 25ish marks just on explanation /:
otherwise, it went well!

please do, really intrigued about revised higher to see what was in it

[S119234]

I absolutely wrecked the first page of the exam with my scale drawing, got it completely and utterly wrong!, oh well, here's hoping I pick up a few other marks later on.

[aroy45]

Can someone explain what I'm doing wrong for 21a


This was posted from The Student Room's iPhone/iPad App

[DragonHeartstring]

(Original post by S119234)
I absolutely wrecked the first page of the exam with my scale drawing, got it completely and utterly wrong!, oh well, here's hoping I pick up a few other marks later on.

Me too-ish! I drew it going west instead of east Just hope that what I got as displacement and bearing is right for what I drew, then I might still pick up marks.

[Scotland 4eva]

Anyone know the answer to mc Q6?

[jahmez95]

(Original post by KeithyDee)
That is not tutor/teacher answers though, just what some people have said.

well here you go then


1E
2A
3C
4C
5C
6D
7B
8D
9B
10C
11B
12E
13D
14E
15D
16A
17A
18D
19B
20B

[CraigFrew]

(Original post by aroy45)
Can someone explain what I'm doing wrong for 21a


This was posted from The Student Room's iPhone/iPad App

Your diagrams wrong, the angle should be 70 degrees

[TheZorse94]

Ill put my answers up for people to correct or agree
21a 15.9km at 157 degree
ii) 3.53m/s
B). 15.9km at 157
ii) 2.94m/s

22ai) 61.2m
ii) 11.475m
B). More likely as ball will not travel at far and reach max height earlier

23) proof
ii). 42318m/s
B) 5.6x10^-3
C) xenon as f=ma as mass is bigger acceleration the same. (very unsure)

24). Proof p/Tk is a constant
B). More collisions with each other and outer walls
C). Stopper could be moved by different pressures acting could change volume. (wrong I think)

25) 1.5A
ii) 3v
iii) 13.5W

B) Internal resistance is lower

26) graph with voltage starting at 0 and levelling out at 12V
B) 5kohms (might be 6kohms)
C)the voltage is the same (not sure)
ii). The capacitance in this instance is the same as the voltage does not change (unsure)

27) proof
B) differential
ii) 5.6
B(a) 1.93v
B(b) 55mm (think its 65)

28) 51 degrees
B) partial internal reflection
ii) 48.8 degrees
C). Sketch shows total internal reflection

29a) 3.3x10^-6m
B) 3.03x10^5
C) yes as it falls within the uncertainty range

30) decrease
B) photoconductive
ii). Current increases
C) 6.75x10^-6

31) 0.0125j (wrong?)
B) alpha

[bob169]

(Original post by KeithyDee)
The displacement was 15.7 +/- 0.2km.

no, it was 16km and +- 10m cos you have to round of 15.7 to 16 and every answer 2 significant figures cos the question was in 2 sig fig, there was no decimal places.

[bob169]

[QUOTE=TheZorse94;37806292]Ill put my answers up for people to correct or agree
21a 15.9km at 157 degree
ii) 3.53m/s
B). 15.9km at 157
ii) 2.94m/s

22ai) 61.2m
ii) 11.475m
B). More likely as ball will not travel at far and reach max height earlier

23) proof
ii). 42318m/s
B) 5.6x10^-3
C) xenon as f=ma as mass is bigger acceleration the same. (very unsure)

24). Proof p/Tk is a constant
B). More collisions with each other and outer walls
C). Stopper could be moved by different pressures acting could change volume. (wrong I think)

25) 1.5A
ii) 3v
iii) 13.5W

B) Internal resistance is lower

26) graph with voltage starting at 0 and levelling out at 12V
B) 5kohms (might be 6kohms)
C)the voltage is the same (not sure)
ii). The capacitance in this instance is the same as the voltage does not change (unsure)

27) proof
B) differential
ii) 5.6
B(a) 1.93v
B(b) 55mm (think its 65)

28) 51 degrees
B) partial internal reflection
ii) 48.8 degrees
C). Sketch shows total internal reflection

29a) 3.3x10^-6m
B) 3.03x10^5
C) yes as it falls within the uncertainty range

30) decrease
B) photoconductive
ii). Current increases
C) 6.75x10^-6

31) 0.0125j (wrong?)
B) alpha

agree with everything but tehcnically speaking 21) answers had to be in 2 sig figures since question was in 2 sig figures dont think that matters unless you put too many

[S119234]

(Original post by DragonHeartstring)
Me too-ish! I drew it going west instead of east Just hope that what I got as displacement and bearing is right for what I drew, then I might still pick up marks.

I also wrote that v=d/t for it, so I'm hoping I maybe pick up a few half marks for formula. And pretty sure I got the time right in the last question, just did everything else wrong!, so annoying as well when you're convinced it's perfect in the exam!

[DragonHeartstring]

(Original post by S119234)
I also wrote that v=d/t for it, so I'm hoping I maybe pick up a few half marks for formula. And pretty sure I got the time right in the last question, just did everything else wrong!, so annoying as well when you're convinced it's perfect in the exam!

I know! I was hoping for a scale drawing in this exam, and then I go and mess it up! Typical

[KeithyDee]

I think things are looking fairly good for me, thanks guys

[Siwel95]

Oh well, now the wait for August begins. I'm still undecided as to open it slowly showing each grade one at a time or just whip it out haha

[KeithyDee]

(Original post by Siwel95)
Oh well, now the wait for August begins. I'm still undecided as to open it slowly showing each grade one at a time or just whip it out haha

I'm just going to whip it out (my philosophy in life ) and see how it goes

Just enjoy the rest of your summer !

[Siwel95]

(Original post by KeithyDee)
I'm just going to whip it out (my philosophy in life ) and see how it goes

Just enjoy the rest of your summer !

haha same goes for you

[S119234]

Could someone say what the answer to 31(a) is ?, I got 0.00002J using D=E/m, but not particularly sure.

Also, for 28(b)(i), would it not be an acceptable answer to say that it's because the angle in air = 90degrees ?, cause that then leads to the critical angle equation.

[Herzschmerz]

Does anyone know what the grade boundary for an A has been the last few years?

[KeithyDee]

(Original post by S119234)
Could someone say what the answer to 31(a) is ?, I got 0.00002J using D=E/m, but not particularly sure.

Also, for 28(b)(i), would it not be an acceptable answer to say that it's because the angle in air = 90degrees ?, cause that then leads to the critical angle equation.

I got some sort of variation of 0.00002

[Siwel95]

(Original post by S119234)
Could someone say what the answer to 31(a) is ?, I got 0.00002J using D=E/m, but not particularly sure.

Also, for 28(b)(i), would it not be an acceptable answer to say that it's because the angle in air = 90degrees ?, cause that then leads to the critical angle equation.

yes i got that for 31a) , as for question 28 i cannot remember the question haha